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Worked Examples · Example 5

Q.Express z=1+i3z=1+i\sqrt3 in polar form.

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For z=1+i3z=1+i\sqrt3: a=1, b=3a=1,\ b=\sqrt3, so r=∣z∣=12+(3)2=1+3=2r=|z|=\sqrt{1^2+(\sqrt3)^2}=\sqrt{1+3}=2. Since a>0,b>0a>0,b>0, zz lies in Quadrant I, so θ=tan⁡−1 ⁣(31)=π3\theta=\tan^{-1}\!\left(\dfrac{\sqrt3}{1}\right)=\dfrac{\pi}{3} (no correction needed in Quadrant I). Substituting into z=r(cos⁡θ+isin⁡θ)z=r(\cos\theta+i\sin\theta) gives z=2(cos⁡π3+isin⁡π3)z=2\left(\cos\dfrac{\pi}{3}+i\sin\dfrac{\pi}{3}\right) …

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