Skip to content
Exercise: Polar Representation · Q18

Q.Express z=1−iz=1-i in polar form.

West Bengal WbchseTextbookSubjectiveImportance★★★★★est
71% · 20/28 Questions
✓ Free question

For z=1−iz=1-i: r=∣z∣=12+(−1)2=2r=|z|=\sqrt{1^2+(-1)^2}=\sqrt2, and (Quadrant IV, as derived above) θ=−π4\theta=-\dfrac{\pi}{4}. Substituting into the polar form gives z=2(cos⁡(−π4)+isin⁡(−π4))z=\sqrt2\left(\cos\left(-\dfrac{\pi}4\right)+i\sin\left(-\dfrac{\pi}4\right)\right).

✓Final answer

z=2(cos⁡(−π4)+isin⁡(−π4))z=\sqrt2\left(\cos\left(-\dfrac{\pi}{4}\right)+i\sin\left(-\dfrac{\pi}{4}\right)\right).

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.