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Mathematics · Ch 7 — Limits and Derivatives

Limits of Polynomial and Rational Functions

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Limits of Polynomial and Rational Functions

Limits of polynomials. A polynomial p(x)=c0+c1x+c2x2+⋯+cnxnp(x) = c_0+c_1x+c_2x^2+\cdots+c_nx^n

is built entirely out of the constant function and the identity function xx, combined only by

addition, subtraction, scalar multiplication and (repeated) multiplication. Since

lim⁡x→ac=c\lim_{x\to a}c=c and lim⁡x→ax=a\lim_{x\to a}x=a (Section 2), applying the product rule repeatedly

gives lim⁡x→axk=ak\lim_{x\to a}x^k=a^k for every positive integer kk, and applying the sum and

scalar-multiple rules to the whole polynomial gives the single most useful fact in this section:

lim⁡x→ap(x)=p(a)\lim_{x\to a} p(x) = p(a)

for every polynomial pp and every real aa -- the limit of a polynomial is found simply by

direct substitution, x=ax=a.

Limits of rational functions. A rational function is a quotient of two polynomials,

f(x)=p(x)q(x)f(x)=\dfrac{p(x)}{q(x)}. By the quotient rule of Section 2, if q(a)≠0q(a)\neq0,

lim⁡x→ap(x)q(x)=p(a)q(a)\lim_{x\to a}\frac{p(x)}{q(x)} = \frac{p(a)}{q(a)}

-- again direct substitution. Two other cases need separate care:

  • If q(a)=0q(a)=0 but p(a)≠0p(a)\neq0, the quotient has no finite limit at aa (it grows without bound as x→ax\to a); this case falls outside the scope of this chapter.
  • If both p(a)=0p(a)=0 and q(a)=0q(a)=0 -- the 0/00/0 indeterminate form flagged in Section 2 -- then (x−a)(x-a) is a common factor of both p(x)p(x) and q(x)q(x) (a consequence of the Factor Theorem from algebra). Cancel the common factor first, then substitute x=ax=a into what remains; the cancelled function agrees with the original everywhere except at x=ax=a itself, and Section 1 already established that the value AT aa never affects the limit.

A standard limit. The following result, used constantly through the rest of this chapter and

into the derivative sections, deserves its own statement and proof.

Theorem. For any positive integer nn and any real aa,

lim⁡x→axn−anx−a=nan−1.\lim_{x\to a}\frac{x^n-a^n}{x-a} = na^{n-1}.

Proof. Factor the numerator using the standard algebraic identity

xn−an=(x−a)(xn−1+xn−2a+xn−3a2+⋯+xan−2+an−1),x^n-a^n = (x-a)\big(x^{n-1}+x^{n-2}a+x^{n-3}a^2+\cdots+xa^{n-2}+a^{n-1}\big),

a sum of exactly nn terms. Since x≠ax\neq a throughout the limiting process, the factor (x−a)(x-a)

cancels with the denominator, leaving

xn−anx−a=xn−1+xn−2a+xn−3a2+⋯+xan−2+an−1.\frac{x^n-a^n}{x-a} = x^{n-1}+x^{n-2}a+x^{n-3}a^2+\cdots+xa^{n-2}+a^{n-1}. …