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Example · Example 3

Q.Insert 44 arithmetic means between 33 and 2323.

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We need 3,A1,A2,A3,A4,233, A_1, A_2, A_3, A_4, 23 to be in A.P. — a total of n+2=6n+2=6 terms with a=3a=3 and last term 2323. By b=a+(n+1)db=a+(n+1)d with n=4n=4: 23=3+5d⇒5d=20⇒d=423=3+5d \Rightarrow 5d=20 \Rightarrow d=4. The means are obtained by repeatedly adding d=4d=4 to a=3a=3: A1=3+4=7A_1=3+4=7, A2=7+4=11A_2=7+4=11, A3=11+4=15A_3=11+4=15, A4=15+4=19A_4=15+4=19, and indeed A4+d=19+4=23A_4+d=19+4=23, which correctly returns the given endpoint. [!ANSWER] 7,11,15,197, 11, 15, 19.

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