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Example · Example 6
Q.

Find the mean deviation about the mean for the following frequency distribution of the marks obtained by 50 students in a class test:

Class interval0-1010-2020-3030-4040-50
Frequency6915146
West Bengal WbchseTextbookSubjectiveImportance★★★★★est
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The class midpoints are xi:5,15,25,35,45x_i:5,15,25,35,45 with frequencies fi:6,9,15,14,6f_i:6,9,15,14,6, so N=6+9+15+14+6=50N=6+9+15+14+6=50. Now ∑fixi=5(6)+15(9)+25(15)+35(14)+45(6)=30+135+375+490+270=1300\sum f_ix_i=5(6)+15(9)+25(15)+35(14)+45(6)=30+135+375+490+270=1300, giving xˉ=130050=26\bar x=\dfrac{1300}{50}=26. The absolute deviations ∣xi−26∣|x_i-26| are 21,11,1,9,1921,11,1,9,19, and weighting by frequency: $f_i|x_i-\bar x|=6(21)+9(11)+15(1)+14(9 …

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