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Exercise: Range and Mean Deviation (U... · Q10

Q.Find the mean deviation about the median for the data: 6,9,3,15,12,8,10,56, 9, 3, 15, 12, 8, 10, 5.

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Sorting the data 6,9,3,15,12,8,10,56,9,3,15,12,8,10,5 gives 3,5,6,8,9,10,12,153,5,6,8,9,10,12,15. Since n=8n=8 is even, the median is the average of the 4th and 5th values: M=8+92=8.5M=\dfrac{8+9}{2}=8.5. The absolute deviations from M=8.5M=8.5, in sorted order, are: ∣3−8.5∣=5.5|3-8.5|=5.5, ∣5−8.5∣=3.5|5-8.5|=3.5, ∣6−8.5∣=2.5|6-8.5|=2.5, ∣8−8.5∣=0.5|8-8.5|=0.5, ∣9−8.5∣=0.5|9-8.5|=0.5, ∣10−8.5∣=1.5|10-8.5|=1.5, ∣12−8.5∣=3.5|12-8.5|=3.5, ∣15−8.5∣=6.5|15-8.5|=6.5. …

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