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Question 23 of 25

Q.The perfect gas equation for 4 g of hydrogen gas is

(a) PV = RT
(b) PV = 2RT
(c) PV = (1/2)RT
(d) PV = 4RT
West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018MCQ· 1mImportance★★★★★
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Use PV=nRTPV=nRT with nn = number of moles = mass ÷ molar mass.

Molar mass of hydrogen gas (H2H_2) is 2 g/mol. For 4 g of H2H_2:

n=4 g2 g/mol=2 moln=\frac{4\ \text{g}}{2\ \text{g/mol}}=2\ \text{mol} …

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