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Exercise · Q11

Q.Convert a speed of 7272 km h−1^{-1} into m s−1^{-1}, and a speed of 55 m s−1^{-1} into km h−1^{-1}.

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Converting 7272 km h−1^{-1} to m s−1^{-1}:

72 km h−1=72×1000 m3600 s=720003600 m s−1=20 m s−172\ \text{km h}^{-1} = 72\times\frac{1000\ \text{m}}{3600\ \text{s}} = \frac{72000}{3600}\ \text{m s}^{-1} = 20\ \text{m s}^{-1}

Converting 55 m s−1^{-1} to km h−1^{-1}:

5 m s−1=5×11000 km×36001 h−1=5×36001000 km h−1=18 km h−15\ \text{m s}^{-1} = 5\times\frac{1}{1000}\ \text{km}\times\frac{3600}{1}\ \text{h}^{-1} = \frac{5\times3600}{1000}\ \text{km h}^{-1} = 18\ \text{km h}^{-1}

A quick way to remember this pair: multiply a km h−1^{-1} value by 518\dfrac{5}{18} to get m s−1^{-1}, and multiply an m s−1^{-1} value by 185\dfrac{18}{5} to get km h−1^{-1} (518×72=20\frac{5}{18}\times72=20; 185×5=18\frac{18}{5}\times5=18, matching both results above).

[!ANSWER] 7272 km h−1=20^{-1} = 20 m s−1^{-1}, and 55 m s−1=18^{-1} = 18 km h−1^{-1}.

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