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Exercise · Q15

Q.The diameter of the Sun is about 1.4×1091.4\times10^{9} m and the diameter of a hydrogen atom is about 1×10−101\times10^{-10} m. Estimate the order of magnitude of the ratio of these two sizes.

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Diameter of SunDiameter of hydrogen atom=1.4×109 m1×10−10 m=1.4×109−(−10)=1.4×1019\frac{\text{Diameter of Sun}}{\text{Diameter of hydrogen atom}} = \frac{1.4\times10^{9}\ \text{m}}{1\times10^{-10}\ \text{m}} = 1.4\times10^{9-(-10)} = 1.4\times10^{19}

This is already in scientific notation a×10ba\times10^{b} with a=1.4a=1.4 and b=19b=19. Since the coefficient a=1.4≤5a=1.4 \le 5, the order of magnitude is 10b=101910^{b} = 10^{19} (no rounding up of the power is needed). …

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