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Question 29 of 31

Q.The displacement of a body of mass 3 kg under the action of a force is S = t²/3 metre. The work done in time 2s by the same force in (J) is

(a) 2
(b) 3.8
(c) 5.2
(d) 2.66
West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018MCQ· 1mImportance★★★★★
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Work done equals the change in kinetic energy — find v(t) by differentiating S(t), then use W=ΔKE.

Given S=t23S=\dfrac{t^2}{3} m, m=3m=3 kg. The body starts from rest (S(0)=0, v(0)=0S(0)=0,\ v(0)=0).

Velocity: v=dSdt=2t3v=\dfrac{dS}{dt}=\dfrac{2t}{3}

At t=2t=2 s: v=2×23=43v=\dfrac{2\times2}{3}=\dfrac{4}{3} m/s

By the work-energy theorem, the work done by the force equals the kinetic energy gained (since it started from rest): …

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