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Exercises · Q8

Q.A borrower pays an EMI of ₹22,920 per month for 12 months on a vehicle loan taken at 18% per annum. Find the loan amount.

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Here EMI=₹22,920\text{EMI}=₹22{,}920, annual rate 18%18\% so monthly rate r=0.015r=0.015, tenure n=12n=12 months, and the loan amount PP is unknown.

Step 1 — Compute (1+r)n(1+r)^n. (1.015)12=1.195618(1.015)^{12} = 1.195618.

Step 2 — Rearrange the EMI formula for PP.

P=EMI×(1+r)n−1r(1+r)n=22,920×0.1956180.015×1.195618=22,920×0.1956180.017934P = \text{EMI}\times\frac{(1+r)^{n}-1}{r(1+r)^{n}} = 22{,}920\times\frac{0.195618}{0.015\times1.195618} = 22{,}920\times\frac{0.195618}{0.017934}

Step 3 — Evaluate.

P≈₹2,50,000P \approx ₹2{,}50{,}000 …

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