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Exercises · Q8

Q.Evaluate ∫(4x3−6x+5) dx\displaystyle\int (4x^{3}-6x+5)\,dx.

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✓ Free question

Apply formula 1 to each term:

∫4x3 dx=4⋅x44=x4,∫−6x dx=−6⋅x22=−3x2,∫5 dx=5x\int 4x^{3}\,dx = 4\cdot\frac{x^{4}}{4}=x^{4}, \qquad \int -6x\,dx = -6\cdot\frac{x^{2}}{2}=-3x^{2}, \qquad \int 5\,dx = 5x

Combining:

∫(4x3−6x+5) dx=x4−3x2+5x+C\int (4x^{3}-6x+5)\,dx = x^{4}-3x^{2}+5x+C

Check by differentiation: ddx[x4−3x2+5x]=4x3−6x+5\dfrac{d}{dx}\left[x^{4}-3x^{2}+5x\right]=4x^{3}-6x+5, matching the original integrand.

✓Final answer

∫(4x3−6x+5) dx=x4−3x2+5x+C\displaystyle\int(4x^{3}-6x+5)\,dx=x^{4}-3x^{2}+5x+C

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