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Exercises · Q13

Q.Evaluate ∫03(x2+1) dx\displaystyle\int_{0}^{3} (x^{2}+1)\,dx using the Fundamental Theorem of Integral Calculus.

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Find an antiderivative of f(x)=x2+1f(x)=x^{2}+1 using formula 1:

F(x)=x33+xF(x)=\frac{x^{3}}{3}+x

Evaluate at the limits:

F(3)=333+3=273+3=9+3=12,F(0)=033+0=0F(3)=\frac{3^{3}}{3}+3=\frac{27}{3}+3=9+3=12, \qquad F(0)=\frac{0^{3}}{3}+0=0

Apply the Fundamental Theorem: …

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