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Exercises · Q10

Q.Find the values of aa, bb, cc and dd if (2ab−3c+14d)=(85620)\begin{pmatrix}2a&b-3\\c+1&4d\end{pmatrix} = \begin{pmatrix}8&5\\6&20\end{pmatrix}.

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✓ Free question

Matching each corresponding pair of elements between the two (equal-order) matrices gives four independent equations:

2a=8,b−3=5,c+1=6,4d=202a=8,\qquad b-3=5,\qquad c+1=6,\qquad 4d=20

Solving each

2a=8⇒a=42a=8 \Rightarrow a=4

b−3=5⇒b=8b-3=5 \Rightarrow b=8

c+1=6⇒c=5c+1=6 \Rightarrow c=5

4d=20⇒d=54d=20 \Rightarrow d=5

Check (independent recomputation): substituting a=4,b=8,c=5,d=5a=4,b=8,c=5,d=5 back into the left-hand matrix gives (2(4)8−35+14(5))=(85620)\begin{pmatrix}2(4)&8-3\\5+1&4(5)\end{pmatrix}=\begin{pmatrix}8&5\\6&20\end{pmatrix}, which matches the right-hand matrix EXACTLY, confirming all four values.

✓Final answer

a=4a=4, b=8b=8, c=5c=5, d=5d=5

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