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Worked Examples · Example 3

Q.Classify each of the following matrices as square, null, diagonal, scalar and/or identity, giving reasons: P=(4004)P=\begin{pmatrix}4&0\\0&4\end{pmatrix}, Q=(1001)Q=\begin{pmatrix}1&0\\0&1\end{pmatrix}, R=(0000)R=\begin{pmatrix}0&0\\0&0\end{pmatrix}, S=(2005)S=\begin{pmatrix}2&0\\0&5\end{pmatrix}.

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Every matrix here is square, since each is 2×22\times2 (equal rows and columns).

Off-diagonal entries are 00 in all four matrices, so ALL four are diagonal matrices.

Matrix P=(4004)P=\begin{pmatrix}4&0\\0&4\end{pmatrix}: diagonal entries are 44 and 44 — equal — so PP is also a SCALAR matrix. Since the common value is 44, not 11, PP is not the identity matrix.

Matrix Q=(1001)Q=\begin{pmatrix}1&0\\0&1\end{pmatrix}: diagonal entries are 11 and 11 — equal, so scalar; and equal to 11, so QQ is also the IDENTITY matrix.

Matrix R=(0000)R=\begin{pmatrix}0&0\\0&0\end{pmatrix}: every entry, diagonal and off-diagonal, is 00. RR is the NULL matrix (a null matrix is trivially also diagonal, since its off-diagonal entries are 0, but 'null' is its primary, most informative classification).

Matrix S=(2005)S=\begin{pmatrix}2&0\\0&5\end{pmatrix}: diagonal entries are 22 and 55 — unequal, so SS is diagonal but NOT scalar (and therefore not identity either).

Check (independent recomputation): re-testing each matrix against the DEFINITIONS directly (square: rows=cols? diagonal: off-diagonal all 0? scalar: diagonal entries all equal? identity: diagonal entries all 1?) reproduces the exact same four classifications, confirming none was misapplied.

✓Final answer

P — square, diagonal, scalar. Q — square, diagonal, scalar, identity. R — square, diagonal, null matrix. S — square, diagonal (not scalar, since its diagonal entries 2 and 5 differ).

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