Skip to content
Question 41 of 49

Q.(i) Copper has completely filled 'd' orbital in its ground state. How can you say that it is a transition element?

(ii) Between Lu(OH)3 and Ce(OH)3 which is more basic and why?
(iii) Complete the following reaction: MnO4-(aq) + C2O4(2-)(aq) + H+(aq) -> ? (1+1+1)
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2023Subjective· 3mImportance★★★★★
84% · 41/49 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

A transition element is defined by having a partially filled d-subshell in the ground state OR in any commonly-occurring oxidation state; Cu qualifies via Cu2+. Basicity of lanthanoid hydroxides falls across the series due to lanthanoid contraction. MnO4- oxidises oxalate to CO2 in acidic medium.

(i) Copper's ground state configuration is [Ar]3d10 4s1 — the d-subshell is indeed completely filled here. But copper's most common oxidation state in compounds is +2 (Cu2+), whose configuration is [Ar]3d9 — an incompletely filled d-subshell. Since the accepted definition of a transition element allows the criterion to be satisfied in the ground state OR in any commonly occurring oxidation state, Cu is classified as a transition element on the strength of Cu2+.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.