Give the electronic configuration of $Ce^{4+}$ and $Co^{2+}$.

Give the electronic configuration of Ce⁴⁺ and Co²⁺.

Question 71 of 72

Ce^{4+}

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2026Subjective· 3mImportance★★★★★

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$Ce^{4+}$ empties out all of cerium's valence electrons, giving it the same electron configuration as the noble gas xenon, while $Co^{2+}$ is formed by cobalt losing only its outer $4s$ electrons, leaving its $3d$ subshell untouched at $3d^7$ .

Cerium and $Ce^{4+}$ : neutral cerium ( $Z=58$ ) has the electronic configuration $Ce: [Xe]4f^15d^16s^2$ To form $Ce^{4+}$ , cerium loses all 4 of its valence electrons — the two $6s$ electrons, the one $5d$ electron, and the one $4f$ electron — giving it a configuration identical to the preceding noble gas: $Ce^{4+}: [Xe]\quad(\text{i.e. } 1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^{10} 5s^2 5p^6)$ ( $Ce^{4+}$ is thus a common, stable oxidation state, since it achieves a fully-filled noble-gas-like configuration.)

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Q.Give the electronic configuration of $Ce^{4+}$ and $Co^{2+}$ .

Concept understanding — Position and Electronic Configuration of Transition Elements

Q.Give the electronic configuration of Ce4+Ce^{4+}Ce4+ and Co2+Co^{2+}Co2+.

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Q.Give the electronic configuration of $Ce^{4+}$ and $Co^{2+}$ .

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