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Exercise · Q16

Q.State the defining structural feature of a transition element. Using this definition, explain why copper (configuration [Ar]3d104s1[\text{Ar}]3d^{10}4s^1 in the free atom) is still classified as a transition element.

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✓ Free question

The definition of a transition element does not require the free atom to have a partially filled d subshell -- it requires that the atom or at least one of its commonly formed ions does.

Copper's free-atom configuration, as established earlier in this chapter, is the anomalous [Ar]3d104s1[\text{Ar}]3d^{10}4s^1, in which the d subshell is already completely filled (d10d^{10}). Taken on its own, this might seem to place copper in the same category as zinc, cadmium and mercury, which are excluded from the transition elements precisely because their d subshell is filled in every state they commonly adopt.

The crucial difference is what happens on ionization. Copper's most common oxidation state in its compounds is +2+2 (as in CuSO4\text{CuSO}_4, CuO\text{CuO}, CuCl2\text{CuCl}_2), formed by losing the single 4s4s electron together with one 3d3d electron: Cu→Cu2++2e−\text{Cu} \rightarrow \text{Cu}^{2+} + 2e^- gives the configuration [Ar]3d9[\text{Ar}]3d^9 -- a genuinely partially filled d subshell, with one vacancy. Because this commonly formed ion, Cu2+\text{Cu}^{2+}, has a partially filled d subshell (even though the neutral atom does not), copper satisfies the "ion" clause of the definition and is correctly classified as a transition element.

This is exactly why Cu2+\text{Cu}^{2+} compounds are strongly coloured (blue, by the same d-d-transition reasoning developed elsewhere in this chapter) and why copper shows genuinely variable oxidation states (+1+1 as Cu+\text{Cu}^+, 3d103d^{10}, and +2+2 as Cu2+\text{Cu}^{2+}, 3d93d^9) -- both hallmarks of true transition-metal behaviour that zinc, cadmium and mercury do not show, since none of their commonly formed ions ever departs from d10d^{10}.

✓Final answer

A transition element is one whose atom, or at least one commonly formed ion, has a partially filled d subshell. Although the free copper atom is [Ar]3d104s1[\text{Ar}]3d^{10}4s^1 (d10d^{10}, completely filled), its common Cu2+\text{Cu}^{2+} ion has the configuration [Ar]3d9[\text{Ar}]3d^9 -- a partially filled d subshell -- so copper still qualifies as a transition element by the ion-based part of the definition.

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