Chemistry · Ch 3 — Haloalkanes and Haloarenes
Comparing SN1 and SN2
Comparing SN1 and SN2
Predicting whether a haloalkane will react by or requires weighing three factors together -- the substrate's structure, the nucleophile's strength, and the solvent -- rather than any one of them in isolation.
Substrate structure is usually the dominant factor. A methyl or primary substrate is essentially forced into , because it cannot form a reasonably stable carbocation and its unhindered backside is readily accessible to a nucleophile. A tertiary substrate is essentially forced into (if it reacts by substitution at all), because steric bulk blocks backside attack almost completely while a tertiary carbocation is comfortably stable. Secondary substrates are the genuine borderline case, capable of either pathway depending on the nucleophile and solvent.
Nucleophile strength then tips a borderline substrate. A strong, good nucleophile in high concentration (e.g. or an alkoxide) pushes a secondary substrate towards ; a weak nucleophile present mainly as the solvent itself (e.g. water or ethanol acting as both solvent and nucleophile, a "solvolysis") favours .
Solvent reinforces the same choice. A polar aprotic solvent (acetone, DMSO, DMF) leaves an added nucleophile unsolvated and reactive, reinforcing ; a polar protic solvent (water, alcohols) stabilises the ionic intermediate and transition states of through hydrogen bonding, reinforcing that pathway, while simultaneously "caging" and weakening any added anionic nucleophile through solvation. …
| Feature | ||
|---|---|---|
| Number of steps | Two (ionisation, then attack) | One (concerted) |
| Rate law | Rate | Rate |
| Kinetic order | First order | Second order |
| Intermediate | Planar carbocation | None (transition state only) |
| Stereochemistry | Racemization (mainly) | Complete inversion (Walden inversion) |
| Substrate preference | Tertiary, benzylic, allylic | Methyl, primary |
| Nucleophile strength needed | Weak nucleophile suffices | Strong nucleophile needed |