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Question 37 of 50

Q.The degree of the differential equation d³y/dx³ + y = (1 + dy/dx)^(1/3) is: OR The value of ∫ e^(a log_e x) dx will be (a ≠ -1), (c is an integration constant in each case):

(a) 1
(b) 2
(c) 3
(d) 4
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2022MCQ· 1mImportance★★★★★
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The 'degree' of a differential equation is the power of its highest-order derivative, once the equation is made free of fractional/negative powers of derivatives — cube both sides to clear the cube root.

Given d3ydx3+y=(1+dydx)1/3\dfrac{d^3y}{dx^3}+y = \left(1+\dfrac{dy}{dx}\right)^{1/3}.

Why we can't read the degree directly: the definition of degree requires the equation to be a polynomial in the derivatives (no fractional powers), but here the right side has a power of 13\dfrac13. So first clear that fractional exponent.

Cube both sides to remove the cube root:

(d3ydx3+y)3=1+dydx\left(\dfrac{d^3y}{dx^3}+y\right)^3 = 1+\dfrac{dy}{dx}

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