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Question 36 of 50

Q.Find differential equation by eliminating a and b from y = e^x (a cos x + b sin x).

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2022Subjective· 5mImportance★★★★★
72% · 36/50 Questions
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Differentiate twice, then algebraically eliminate the two arbitrary constants a,ba,b to leave a relation purely in y,y′,y′′y,y',y''.

Given y=ex(acos⁡x+bsin⁡x)y = e^x(a\cos x+b\sin x).

Differentiate once (product rule):

y′=ex(acos⁡x+bsin⁡x)+ex(−asin⁡x+bcos⁡x)y' = e^x(a\cos x+b\sin x) + e^x(-a\sin x+b\cos x)

=ex[(a+b)cos⁡x+(b−a)sin⁡x]= e^x\big[(a+b)\cos x+(b-a)\sin x\big]

Differentiate again:

y′′=ex[(a+b)cos⁡x+(b−a)sin⁡x]+ex[−(a+b)sin⁡x+(b−a)cos⁡x]y'' = e^x\big[(a+b)\cos x+(b-a)\sin x\big] + e^x\big[-(a+b)\sin x+(b-a)\cos x\big]

=ex[(a+b+b−a)cos⁡x+(b−a−a−b)sin⁡x]= e^x\big[(a+b+b-a)\cos x + (b-a-a-b)\sin x\big]

=ex[2bcos⁡x−2asin⁡x]= e^x\big[2b\cos x - 2a\sin x\big]

Eliminate a,ba,b. Form y′′−2y′+2yy''-2y'+2y and check the coefficients of cos⁡x\cos x and sin⁡x\sin x cancel:

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