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Question 47 of 49

Q.Let R\mathbb{R} be the set of real numbers and f:R→Rf : \mathbb{R} \to \mathbb{R}, g:R→Rg : \mathbb{R} \to \mathbb{R} are two mappings such that f(x)=∣x∣−x2f(x) = |x| - x^2, g(x)=2x+3;  ∀x∈Rg(x) = 2x + 3;\; \forall x \in \mathbb{R}, then the value of (g∘f)(−3)(g \circ f)(-3) is

(a) 99
(b) −9-9
(c) 66
(d) −6-6
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
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Composite (g∘f)(−3)=g(f(−3))(g\circ f)(-3)=g(f(-3)): first f(−3)=−6f(-3)=-6, then g(−6)=−9g(-6)=-9.

Evaluating a composition of functions is a CBSE/NCERT Class 12 relations and functions basic.

First apply ff:

f(−3)=∣−3∣−(−3)2=3−9=−6.f(-3) = |-3| - (-3)^2 = 3 - 9 = -6.

Then apply gg to this result: …

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