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Example · Example 6

Q.If f(x)=2x+3f(x) = 2x + 3 and g(x)=x2−1g(x) = x^2 - 1, find (g∘f)(x)(g \circ f)(x) and (f∘g)(x)(f \circ g)(x). Are they equal?

West Bengal WbchseTextbookSubjectiveImportance★★★★★
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(g∘f)(x)=g(f(x))=g(2x+3)=(2x+3)2−1=(4x2+12x+9)−1=4x2+12x+8(g\circ f)(x) = g(f(x)) = g(2x+3) = (2x+3)^2 - 1 = (4x^2+12x+9) - 1 = 4x^2+12x+8.

(f∘g)(x)=f(g(x))=f(x2−1)=2(x2−1)+3=2x2−2+3=2x2+1(f\circ g)(x) = f(g(x)) = f(x^2-1) = 2(x^2-1)+3 = 2x^2-2+3 = 2x^2+1. …

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