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Question 48 of 49

Q.Statement (Q): f:R→Rf : \mathbb{R} \to \mathbb{R} is a function defined as f(x)=[x]f(x) = [x], greatest integer function, f(x)f(x) is not onto function. Reason (R): A function F:X→YF : X \to Y is one-one if F(a)=F(b)⇒a=bF(a) = F(b) \Rightarrow a = b. Alternatives:

(a) (Q) and (R) both are true, and (R) is a correct explanation of (Q)
(b) (Q) and (R) both are true, but (R) is not a correct explanation of (Q)
(c) (Q) is true but (R) is false
(d) (Q) is false but (R) is true
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
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(Q) is true (the floor function is not onto), and (R) is a true statement about one-one maps — but (R) explains injectivity, not the surjectivity claim in (Q), so it is not the correct explanation.

Onto (surjective) vs one-one (injective) functions is a CBSE/NCERT Class 12 relations and functions distinction.

(Q): f(x)=[x]f(x)=[x] (greatest integer function) maps R→R\mathbb{R}\to\mathbb{R}, but its range is only the set of integers Z\mathbb{Z}, which is a proper subset of R\mathbb{R}. So ff is not onto — (Q) is true.

(R): The statement "FF is one-one if F(a)=F(b)⇒a=bF(a)=F(b)\Rightarrow a=b" is the correct definition of a one-one (injective) function — true.

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