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Exercise: One-One and Onto Functions · Q19

Q.Let f:Z→Zf : \mathbb{Z} \to \mathbb{Z} be defined by f(x)=x2f(x) = x^2. Determine whether ff is one-one and whether it is onto.

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Not one-one: f(1)=1f(1)=1 and f(−1)=1f(-1)=1, so f(1)=f(−1)f(1)=f(-1) but 1≠−11\neq-1. Not one-one.

Not onto: the range of ff is {0,1,4,9,16,… }\{0,1,4,9,16,\dots\}, the perfect squares (all ≥0\geq0). But the codomain is all of Z\mathbb{Z}, which includes negative integers. Take y=−1y=-1: no integer xx satisfies x2=−1x^2=-1. …

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