Q.For what value of λ are the vectors a=2i^+λj^+k^ and b=i^−2j^+3k^ perpendicular?
West Bengal WbchseTextbookSubjectiveImportance★★★★★
51% · 26/51 Questions
✓ Free question
Concept understanding — Scalar (Dot) Product
For non-zero vectors a,b with included angle θ (0≤θ≤π), the scalar (dot) product is the numbera⋅b=∣a∣∣b∣cosθ.
Geometric meaning (projection).a⋅b=∣a∣×(projection of b on a), and the projection of b on a is ∣a∣a⋅b (symmetrically, projection of a on b is ∣b∣a⋅b).
Core properties.
Commutative:a⋅b=b⋅a.
Sign follows the angle: positive for 0≤θ<π/2, zero at θ=π/2, negative for π/2<θ≤π. In particular a⋅b=0⟺a=0 or b=0 or a⊥b — for two non-zero vectors, a⋅b=0 is exactly the perpendicularity test.
a⋅a=∣a∣2 (often written a2), so ∣a∣=a⋅a.
i^⋅i^=j^⋅j^=k^⋅k^=1 and i^⋅j^=j^⋅k^=k^⋅i^=0 (they're mutually perpendicular unit vectors).
Distributive:a⋅(b+c)=a⋅b+a⋅c, and likewise for subtraction and for the right factor.
Identities (proved exactly like (x+y)2 for numbers): ∣a+b∣2=∣a∣2+∣b∣2+2a⋅b; ∣a−b∣2=∣a∣2+∣b∣2−2a⋅b; (a+b)⋅(a−b)=∣a∣2−∣b∣2.
Coordinate formula: for a=a1i^+a2j^+a3k^, b=b1i^+b2j^+b3k^: a⋅b=a1b1+a2b2+a3b3.
Angle formula:θ=cos−1(∣a∣∣b∣a⋅b).
Triangle/Cauchy–Schwarz-type inequalities:∣a+b∣≤∣a∣+∣b∣ and ∣a⋅b∣≤∣a∣∣b∣.
Because the dot product pins down the angle unambiguously between 0 and π, it is the preferred tool whenever a problem asks for 'the angle between two vectors' (the cross product only ever returns the acute angle, since sinθ≥0 throughout [0,π]).