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Exercise: Section Formula · Q20

Q.Find the position vector of the midpoint of the line segment joining A(3,−2,1)A(3,-2,1) and B(1,4,−3)B(1,4,-3).

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✓ Free question

A(3,−2,1)A(3,-2,1), B(1,4,−3)B(1,4,-3).

Midpoint=(3+12,−2+42,1+(−3)2)=(2,1,−1).\text{Midpoint}=\left(\frac{3+1}{2},\frac{-2+4}{2},\frac{1+(-3)}{2}\right)=(2,1,-1).

✓Final answer

(2,1,−1)(2,1,-1)

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