Skip to content

Physics · Ch 7 — Alternating Current

Power in an AC Circuit: Average Power and Power Factor

7.13

Power in an AC Circuit: Average Power and Power Factor

Instantaneous power. The instantaneous power delivered to any AC circuit is simply the product of the instantaneous voltage and instantaneous current, p=vip=vi. For a general series circuit with v=v0sin⁡ωtv=v_0\sin\omega t and current lagging (or leading) by phase angle ϕ\phi, i=i0sin⁡(ωt−ϕ)i=i_0\sin(\omega t-\phi), so

p=v0i0sin⁡ωt sin⁡(ωt−ϕ)p = v_0 i_0\sin\omega t\,\sin(\omega t-\phi)

Averaging over a full cycle. Using the trigonometric identity sin⁡Asin⁡B=12[cos⁡(A−B)−cos⁡(A+B)]\sin A\sin B=\tfrac12[\cos(A-B)-\cos(A+B)], this becomes

p=v0i02[cos⁡ϕ−cos⁡(2ωt−ϕ)]p = \frac{v_0 i_0}{2}\left[\cos\phi - \cos(2\omega t-\phi)\right]

The first term, 12v0i0cos⁡ϕ\tfrac12 v_0 i_0\cos\phi, is a CONSTANT (independent of time). The second term oscillates at TWICE the original frequency and, being a pure cosine, averages to exactly zero over any whole number of cycles. So the average power over a complete cycle is simply the constant first term:

Pavg=v0i02cos⁡ϕ=v02⋅i02cos⁡ϕP_{avg} = \frac{v_0 i_0}{2}\cos\phi = \frac{v_0}{\sqrt2}\cdot\frac{i_0}{\sqrt2}\cos\phi

Substituting the rms values Vrms=v0/2V_{rms}=v_0/\sqrt2 and Irms=i0/2I_{rms}=i_0/\sqrt2 from Section 7.2,

Pavg=VrmsIrmscos⁡ϕ\boxed{P_{avg} = V_{rms}I_{rms}\cos\phi}

Power factor. The quantity cos⁡ϕ\cos\phi appearing here is called the power factor of the circuit -- it is a pure number, between 00 and 11, that says what FRACTION of the product VrmsIrmsV_{rms}I_{rms} (sometimes called the apparent power) is actually converted into genuine average power. When ϕ=0\phi=0 (voltage and current in phase, as in a pure resistor), cos⁡ϕ=1\cos\phi=1 and every bit of VrmsIrmsV_{rms}I_{rms} is real power; when ϕ=90∘\phi=90^\circ (as in a pure inductor or pure capacitor), cos⁡ϕ=0\cos\phi=0 and NO average power is delivered at all, however large the rms voltage and current individually are. …