Skip to content

Physics · Ch 7 — Alternating Current

The LR Series Circuit

7.8

The LR Series Circuit

Setting up the circuit. A resistor RR and an inductor LL are connected in SERIES to an AC source v=v0sin⁡ωtv=v_0\sin\omega t, so the SAME instantaneous current ii flows through both elements at every instant -- this shared current is the natural reference phasor to build the diagram around.

The two voltage phasors. The voltage across the resistor, VR=IRV_R=IR, is IN PHASE with the current (Section 7.4), so its phasor is drawn along the same direction as the current phasor II. The voltage across the inductor, VL=IXLV_L=IX_L, LEADS the current by 90∘90^\circ (Section 7.5), so its phasor is drawn at right angles to II, ahead of it in the direction of rotation.

Adding the two phasors. Since VRV_R and VLV_L are at right angles to each other, and the source voltage vv must equal their (phasor) sum at every instant, the resultant applied-voltage phasor VV is the diagonal of the rectangle formed by VRV_R and VLV_L -- found, by the Pythagorean theorem, as

V=VR2+VL2=(IR)2+(IXL)2=IR2+XL2V = \sqrt{V_R^2+V_L^2} = \sqrt{(IR)^2+(IX_L)^2} = I\sqrt{R^2+X_L^2}

Reading off the impedance. Comparing this with the Ohm's-law-shaped relation V=IZV=IZ identifies the circuit's impedance directly:

Z=R2+XL2Z = \sqrt{R^2+X_L^2}

The phase angle. The angle ϕ\phi by which the resultant voltage phasor VV sits AHEAD of the current phasor II (equivalently, the angle by which the current LAGS the voltage) is read off the same right-angled triangle as

tan⁡ϕ=VLVR=IXLIR=XLR\tan\phi = \frac{V_L}{V_R} = \frac{IX_L}{IR} = \frac{X_L}{R} …

Figure 1Impedance-triangle phasor diagram for a series LR circuit

What this figure shows. A right-angled triangle is drawn (the 'impedance triangle'), with the horizontal base leg labelled RR, the vertical leg (drawn going straight up from the right end of the base) labelled XLX_L, and the hypotenuse -- drawn from the origin at the left end of the base up to the top of the vertical leg -- labelled ZZ. The angle between the base (RR) and the hypotenuse (ZZ), at the origin, is marked with a small arc and labelled ϕ\phi. Beside this triangle, a separate small phasor diagram is drawn with the current phasor II along the horizontal reference direction, the resistor's voltage phasor VRV_R drawn along the SAME horizontal direction as II (in phase with it), and the inductor's voltage phasor VLV_L drawn at 90∘90^\circ ANTICLOCKWISE from VRV_R (ahead of it); the resultant applied voltage phasor VV is drawn as the diagonal of the rectangle formed by VRV_R and VLV_L, at angle ϕ\phi above VRV_R, with a small arc marking this same angle ϕ\phi -- showing tha …