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Question 26 of 31

Q.The energy of an electromagnetic wave is distributed along its electric and magnetic fields in the ratio

(a) 1 : 1
(b) C² : 1
(c) √C : 1
(d) C : 1.
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2024MCQ· 1mImportance★★★★★
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Because E=cBE = cB in an electromagnetic wave and the energy densities involve E2E^2 and B2B^2 with c2=1/(μ0ε0)c^2 = 1/(\mu_0\varepsilon_0), the electric and magnetic energy densities always come out equal.

The energy density (energy per unit volume) stored in the electric field of an EM wave is

uE=(1/2)ε0E2u_E = (1/2)\varepsilon_0 E^2

and in the magnetic field,

uB=B22μ0u_B = \dfrac{B^2}{2\mu_0}

In an electromagnetic wave, the electric and magnetic field magnitudes are related by E=cBE = cB, where c=1/μ0ε0c = 1/\sqrt{\mu_0\varepsilon_0}.

Substitute B=E/cB = E/c into uBu_B: …

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