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Physics · Ch 2 — Electrostatic Potential and Capacitance

Electric Potential Due to a Point Charge

2.4

Electric Potential Due to a Point Charge

The potential due to a single, isolated point charge qq is the most fundamental potential formula in electrostatics, since the potential of any more complicated charge distribution is ultimately assembled by adding up contributions of exactly this same form (Section 2.6).

Consider a point charge qq fixed at the origin, and a point PP at distance rr from it. The potential at PP, by definition, is the work done per unit charge bringing a positive test charge from infinity to PP:

V(r)=−∫∞rE(r′) dr′=−∫∞rkqr′2 dr′V(r) = -\int_{\infty}^{r} E(r')\, dr' = -\int_{\infty}^{r} \frac{kq}{r'^2}\, dr'

where k=1/(4πϵ0)=9×109 N m2/C2k = 1/(4\pi\epsilon_0) = 9\times 10^9\ \text{N}\,\text{m}^2/\text{C}^2 and the field of the point charge, E(r′)=kq/r′2E(r') = kq/r'^2, has been substituted directly (the field points radially outward for q>0q>0, along the same direction as the displacement, so the integral needs no extra sign adjustment beyond the one already written). Carrying out the integration,

V(r)=−kq[−1r′]∞r=−kq(−1r−0)=kqrV(r) = -kq\left[-\frac{1}{r'}\right]_{\infty}^{r} = -kq\left(-\frac{1}{r} - 0\right) = \frac{kq}{r}

giving the standard result

V(r)=kqr=q4πϵ0rV(r) = \frac{kq}{r} = \frac{q}{4\pi\epsilon_0 r} …