Skip to content
Question 27 of 43

Q.What is an equipotential surface? Show that the electric field is always normal to an equipotential surface.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2016Subjective· 3mImportance★★★★★
63% · 27/43 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

On an equipotential surface V is constant everywhere, so moving a test charge along the surface does zero work — which is only possible if E has no component along the surface, i.e. E is everywhere normal to it.

An equipotential surface is defined as a surface at every point of which the electric potential has the same value.

Proof that E ⊥ equipotential surface: Let a test charge q₀ be displaced by a small vector dl along the equipotential surface, from one point to a neighbouring point on the same surface. The work done by the electric field is

dW = q₀E·dl = q₀(E cosθ) dl

But since both points lie on the same equipotential surface, the potential does not change, so dV = 0, and since dW = −q₀dV = 0, we get

E·dl = 0 ⟹ E cosθ = 0 (as E, dl ≠ 0) ⟹ θ = 90°

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.