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Physics · Ch 2 — Electrostatic Potential and Capacitance

Relation Between Electric Field Intensity and Potential

2.3

Relation Between Electric Field Intensity and Potential

Because electric field E⃗\vec{E} and electric potential VV describe exactly the same electrostatic field, one as a vector and the other as a scalar, an exact mathematical relation must connect the two -- and it takes the form of a derivative in one direction and an integral in the other.

From potential to field (differentiation). Consider a small displacement dldl along the direction in which the field E⃗\vec{E} points, moving a test charge q0q_0 through it. The work done by the field itself on the charge over this small step is dWfield=q0E dldW_{\text{field}} = q_0 E\, dl; the work an EXTERNAL agent must supply to move the charge quasi-statically (balancing the field's force at every instant) is therefore dWext=−q0E dldW_{\text{ext}} = -q_0 E\, dl. Dividing by q0q_0, this external work per unit charge is, by definition, the change in potential over that step, dVdV:

dV=−E dl⟹E=−dVdldV = -E\, dl \quad \Longrightarrow \quad E = -\frac{dV}{dl}

So the component of the electric field along any direction equals minus the rate at which potential falls off in that direction. Two consequences follow immediately: first, the electric field points in the direction of the STEEPEST DECREASE of potential (never toward increasing potential, for a positive test charge to be pushed the way it actually is); second, wherever the field is strong, potential must be changing rapidly with position, and wherever the field is weak (or zero), potential must be changing slowly (or be constant) -- exactly the picture equipotential surfaces make visual in Section 2.7.

From field to potential (integration). Running the same relation the other way, the potential difference between two points AA and BB is recovered by integrating the field along any path joining them:

VB−VA=−∫ABE⃗⋅dl⃗V_B - V_A = -\int_A^B \vec{E}\cdot d\vec{l}

Special case: a uniform field. Between the plates of a parallel plate capacitor (Section 2.13), the field EE is uniform and directed straight from the positive plate to the negative plate. Integrating the relation above along a straight path of length dd between the plates, in the direction of E⃗\vec{E}, gives simply …