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Question 56 of 58

Q.For a semicircular conductor ( shown in the diagram ) the magnetic field at the centre of the conductor is

(a) μ₀i/2a
(b) μ₀i/2πa
(c) zero
(d) μ₀i/4a
A semicircular loop of radius a carrying current i (arrow shows current direction along the arc), with straight conductor segments — Class 12 Physics question
Figure
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
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A semicircle contributes half the central field of a full circular loop, B = μ₀i/4a. The straight segments lie along lines through the centre, so dl × r = 0 and they add nothing. Option (d).

Step 1 — field of a full circular loop at its centre: B_full = μ₀i/2a. A semicircle subtends half the angle, so B_arc = μ₀i/4a (using the Biot–Savart law, NCERT/CBSE Class 12 Physics).

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