Skip to content
Question 3 of 9

Q.Find the length of the chord intercepted by the circle x2+y2−x+3y−22=0x^2+y^2-x+3y-22=0 on the line y=x−3y=x-3.

Yanam BieapBIEAP Intermediate Board 2024Subjective· 4mImportance★★★★★
33% · 3/9 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Find the circle's centre/radius, the perpendicular distance from the centre to the line, then use chord length=2r2−d2\text{chord length}=2\sqrt{r^2-d^2}.

Circle: x2+y2−x+3y−22=0x^2+y^2-x+3y-22=0. Here 2g=−1⇒g=−122g=-1\Rightarrow g=-\tfrac12, 2f=3⇒f=322f=3\Rightarrow f=\tfrac32, c=−22c=-22.

Centre =(−g,−f)=(12,−32)=(-g,-f)=\left(\tfrac12,-\tfrac32\right)

Radius r=g2+f2−c=14+94+22=492=72r=\sqrt{g^2+f^2-c}=\sqrt{\tfrac14+\tfrac94+22}=\sqrt{\tfrac{49}{2}}=\dfrac{7}{\sqrt2}

Line: y=x−3y=x-3, i.e. x−y−3=0x-y-3=0.

Perpendicular distance from centre to the line: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.