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Question 7 of 9

Q.Find the equation of the common chord of the circles x2+y2−4x−4y+3=0x^2 + y^2 - 4x - 4y + 3 = 0, x2+y2−5x−6y+4=0x^2 + y^2 - 5x - 6y + 4 = 0.

Yanam BieapBIEAP Intermediate Board 2025Subjective· 2mImportance★★★★★
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The common chord of two intersecting circles S1=0S_1=0 and S2=0S_2=0 is the line S1−S2=0S_1-S_2=0.

Let S1:x2+y2−4x−4y+3=0S_1: x^2+y^2-4x-4y+3=0 and S2:x2+y2−5x−6y+4=0S_2: x^2+y^2-5x-6y+4=0.

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