Find the equation of the circle whose end points of a diameter are (1, 2), (4, 6).

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(1, 2), (4, 6)

Yanam BieapBIEAP Intermediate Board 2025Subjective· 2mImportance★★★★★

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When $(x_1,y_1)$ and $(x_2,y_2)$ are the ends of a diameter, the circle's equation is $(x-x_1)(x-x_2)+(y-y_1)(y-y_2)=0$ .

Given the diameter endpoints $(1,2)$ and $(4,6)$ , the circle's equation is

$(x-1)(x-4)+(y-2)(y-6)=0.$

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Q.Find the equation of the circle whose end points of a diameter are $(1, 2), (4, 6)$ .