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Exercise 2.2 · Q5

Q.A local train from Mumbai leaves every 40 minutes from the station. When inquired by a passenger, the help desk executive informed that the train had already left 10 minutes ago. If this information was given at 10:15 a.m.

a) At what time did the train leave the station?
b) At what time will the next train leave the station?
c) For how long will that man has to wait for the next train?
d) Find the angle formed between the minute hand and the hour hand when the passenger will board the next train?
Yanam CbseNCERTSubjective· 3mImportance★★★★★est
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Working backward and forward from the 10:15 am announcement: the missed train left at 10:05, the next leaves at 10:45, the wait is 30 minutes, and the hands are 52.5∘52.5^\circ apart at boarding time.

Clock-time addition/subtraction; angle between hands θ=∣30H−5.5M∣\theta = |30H-5.5M| degrees (HH = hour, MM = minutes).

Given: trains leave every 4040 minutes; at 10 ⁣: ⁣1510\!:\!15 am a passenger is told the last train left 1010 minutes earlier.

  1. (a) Time the train left: subtract 1010 minutes from 10 ⁣: ⁣1510\!:\!15 am:

10 ⁣: ⁣15−0 ⁣: ⁣10=10 ⁣: ⁣05 am10\!:\!15 - 0\!:\!10 = 10\!:\!05\ \text{am}

  1. (b) Time of the next train: add the 4040-minute interval to the departure just found:

10 ⁣: ⁣05+0 ⁣: ⁣40=10 ⁣: ⁣45 am10\!:\!05 + 0\!:\!40 = 10\!:\!45\ \text{am}

  1. (c) Waiting time: from the moment of enquiry (10 ⁣: ⁣1510\!:\!15 am) to the next departure (10 ⁣: ⁣4510\!:\!45 am):

10 ⁣: ⁣45−10 ⁣: ⁣15=30 minutes10\!:\!45 - 10\!:\!15 = 30\ \text{minutes}

  1. (d) Angle at boarding (10:45 am): here H=10H=10, M=45M=45: θ=∣30(10)−5.5(45)∣=∣300−247.5∣=52.5∘\theta = |30(10) - 5.5(45)| = |300 - 247.5| = 52.5^\circ …

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