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Worked Examples · Example 13.8

Q.What is the length of a simple pendulum, which ticks seconds?

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A seconds pendulum has a time period of exactly 2 seconds (one tick per second). Using T=2πL/gT = 2\pi \sqrt{L/g} with g=9.8 m/s2g = 9.8\ \text{m/s}^2, the required length is approximately 1.0 m (more precisely, 0.994 m).

Why "seconds pendulum" means a 2-second period

The phrase "ticks seconds" is the classic exam trap. A pendulum that "ticks seconds" does not have a period of 1 second. Think about it: a pendulum makes one complete to-and-fro swing in one period. On a clock, the "tick" happens when the pendulum passes through the lowest point — that's half a period. So if it ticks once per second, the full period (tick to tick to tick) is 2 seconds.

Watch out

Many students assume "ticks seconds" means T=1 sT = 1\ \text{s}. That gives L≈0.25 mL \approx 0.25\ \text{m}, which is wrong. The correct period is 2 seconds.

The physics in one line

For small oscillations, a simple pendulum is a simple harmonic oscillator. The restoring force is proportional to displacement, and the time period depends only on length LL and gravity gg:

T=2πLgT = 2\pi \sqrt{\frac{L}{g}}

This formula comes from equating the restoring torque (−mgLsin⁡θ-mgL\sin\theta) to IαI\alpha (with I=mL2I = mL^2), then using the small-angle approximation sin⁡θ≈θ\sin\theta \approx \theta. The result is SHM with angular frequency ω=g/L\omega = \sqrt{g/L}, and T=2π/ωT = 2\pi/\omega.

Step-by-step solution

  1. Identify the period. The pendulum ticks once per second. One tick is half a period (the pendulum goes from one extreme to the other). So the full period is:

T=2 sT = 2\ \text{s}

  1. Write the pendulum formula.

T=2πLgT = 2\pi \sqrt{\frac{L}{g}}

  1. Solve for LL. Square both sides:

T2=4π2LgT^2 = 4\pi^2 \frac{L}{g}

Rearrange:

L=gT24π2L = \frac{g T^2}{4\pi^2}

  1. Plug in the numbers. …

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