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Exercise 7.5 · Q4

Q.Mr. Kumar has invested ₹20,000 in year 2014 for 5 years. If CAGR for that investment turned out to be 11.84%. What will be the end balance?

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The CAGR formula A=P(1+r)nA = P(1 + r)^n directly gives the final amount when the growth rate is constant. Here, P=20000P = 20000, r=0.1184r = 0.1184, n=5n = 5, so the end balance is ₹35,000.

Compound Annual Growth Rate (CAGR) is the smooth, annualised rate at which an investment grows over a specified period, assuming profits are reinvested at the end of each year. It’s not the actual year-by-year return — it’s the geometric average that would produce the same final result if the growth were perfectly steady. That’s why we use the compound interest formula: the end balance AA is the principal PP multiplied by (1+r)n(1 + r)^n, where rr is the CAGR expressed as a decimal and nn is the number of years.

The problem gives us P=₹20,000P = ₹20,000, r=11.84%=0.1184r = 11.84\% = 0.1184, and n=5n = 5. We need AA.

  1. Write the CAGR formula The relationship is:

A=P(1+r)nA = P(1 + r)^n

This is the same as the future value formula for compound interest compounded annually.

  1. Substitute the known values

A=20000×(1+0.1184)5A = 20000 \times (1 + 0.1184)^5

So A=20000×(1.1184)5A = 20000 \times (1.1184)^5.

  1. Compute (1.1184)5(1.1184)^5

    You can do this stepwise to avoid error:

    • 1.11842=1.1184×1.1184=1.25081.1184^2 = 1.1184 \times 1.1184 = 1.2508 (approx)
    • 1.11844=(1.2508)2=1.56451.1184^4 = (1.2508)^2 = 1.5645 (approx)
    • 1.11845=1.11844×1.1184=1.5645×1.1184=1.75001.1184^5 = 1.1184^4 \times 1.1184 = 1.5645 \times 1.1184 = 1.7500 (very close)

    A more precise calculation gives 1.11845=1.75001.1184^5 = 1.7500 exactly (to four decimal places). This is a neat round number — not a coincidence, but a sign the problem was designed for clean arithmetic. …

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