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Exercise 7.5 · Q5

Q.Mr. Naresh has bought 200 shares of City Look Company at ₹100 each in 2015. After selling them he has received ₹30,000 which accounts for 22.47% CAGR. Calculate the number of years for which he was holding the shares.

Yanam CbseNCERTSubjective· 3mImportance★★★★★
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The CAGR formula CAGR=(FinalInitial)1/n−1CAGR = \left(\frac{Final}{Initial}\right)^{1/n} - 1 is used to find the holding period nn. Given initial investment ₹20,000, final amount ₹30,000, and CAGR 22.47%, solving gives n=2n = 2 years.

The key here is understanding what CAGR (Compound Annual Growth Rate) actually measures. It’s the constant annual rate at which an investment would have grown if it compounded smoothly over the entire period — ignoring any ups and downs in between. The formula is:

CAGR=(Final ValueInitial Value)1n−1CAGR = \left( \frac{Final\ Value}{Initial\ Value} \right)^{\frac{1}{n}} - 1

Where nn is the number of years. We know the CAGR, the initial and final values, and we need nn. So we’ll rearrange the formula to solve for nn.

Let’s work through it step by step.

  1. Find the initial investment.

    Mr. Naresh bought 200 shares at ₹100 each.

    Initial value =200×100=₹20,000= 200 \times 100 = ₹20,000.

  2. Identify the final amount.

    He received ₹30,000 after selling. So final value =₹30,000= ₹30,000.

  3. Write the CAGR equation.

    CAGR is given as 22.47%, which as a decimal is 0.22470.2247.

0.2247=(3000020000)1n−10.2247 = \left( \frac{30000}{20000} \right)^{\frac{1}{n}} - 1

  1. Simplify the ratio.

3000020000=1.5\frac{30000}{20000} = 1.5

So the equation becomes:

0.2247=(1.5)1n−10.2247 = (1.5)^{\frac{1}{n}} - 1

  1. Isolate the exponential term. Add 1 to both sides:

1.2247=(1.5)1n1.2247 = (1.5)^{\frac{1}{n}}

  1. Take natural logarithms on both sides. This is the cleanest way to bring the exponent 1/n1/n down.

log⁡(1.2247)=1n⋅log⁡(1.5)\log(1.2247) = \frac{1}{n} \cdot \log(1.5)

  1. Compute the logs (or use given values). You can use approximate values: …

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