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NCERT Exemplar · Q54

Q.How will you carry out the following conversion: aniline (C6H5NH2) is to be converted into 1-bromo-3-nitrobenzene (m-bromonitrobenzene, a benzene ring bearing –Br and –NO2 groups meta to each other)?

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A meta-Br/NO2 arrangement cannot be built by direct electrophilic substitution (both groups are o/p directors). Instead the aniline nitrogen is used to position –Br (para) and –NO2 (ortho) and is then removed by diazotisation + deamination, leaving –Br and –NO2 meta to one another.

Step 1 – Protect

Aniline + (CH3CO)2O → acetanilide (moderates the ring so bromination stops cleanly at mono-substitution).

Step 2 – Bromination

Acetanilide + Br2 / CH3COOH → p-bromoacetanilide (–NHCOCH3 at C1, –Br at C4; the acetamido group directs para).

Step 3 – Nitration

p-Bromoacetanilide + HNO3/H2SO4 → 4-bromo-2-nitroacetanilide. The –NO2 enters ortho to the acetamido group (C2).

Step 4 – Hydrolysis

4-Bromo-2-nitroacetanilide + H3O+ → 4-bromo-2-nitroaniline (–NH2 at C1, –NO2 at C2, –Br at C4).

Step 5 – Diazotisation and deamination

  • 4-Bromo-2-nitroaniline + NaNO2/HCl at 273–278 K → diazonium salt. …

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