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Exercises · 2.17

Q.Figure 2.14 gives the xx-tt plot of a particle in one-dimensional motion. Three different equal intervals of time are shown. In which interval is the average speed greatest, and in which is it the least? Give the sign of average velocity for each interval.

Figure 2.14
Figure 2.14
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On an xx-tt graph the magnitude of the slope is the average speed and its sign is the sign of the average velocity. Interval 3 (the steep fall) has the largest slope magnitude, so the greatest average speed; interval 2 (near the flat maximum) has the smallest slope magnitude, so the least average speed. The velocity is positive where xx increases (intervals 1 and 2) and negative where xx decreases (interval 3).

Concept

Over an interval,

average velocity=ΔxΔt,average speed=path lengthΔt.\text{average velocity} = \frac{\Delta x}{\Delta t}, \qquad \text{average speed} = \frac{\text{path length}}{\Delta t}.

For motion along a line without reversal within an interval, the average speed equals the magnitude of the average velocity, i.e. the magnitude of the chord's slope on the xx-tt graph. The three intervals are equal in duration (Δt\Delta t the same), so comparing average speeds just means comparing how much xx changes.

Comparing the intervals

  • Interval 1 (gentle rise): xx increases by a moderate amount, so a moderate positive slope. Average velocity >0> 0. …

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