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Worked Examples · Example 2

Q.Consider a classroom having seating capacity of 30 students. The first 29 students have a choice to sit but the 30th student can only sit on the one remaining seat. Therefore, the degrees of freedom is 29.

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With n=30n=30 seats, 2929 students choose freely and the last is fixed, so the degrees of freedom =n−1=29=n-1=29.

Degrees of freedom=n−1\text{Degrees of freedom} = n - 1

  • nn = total number of items (here, students/seats)
  • The "−1-1" is the single constraint (the last value is determined by the rest).
  1. Total seats/students: n=30n = 30.
  2. The first 2929 students each have a free choice of the remaining seats. …

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