Q.Match the items in Column I with those in Column II and select the correctly matched option from those given below : Column I (Cross) 1. Mendelian monohybrid 2. Mendelian dihybrid 3. Incomplete dominance 4. Test cross (monohybrid) Column II (Phenotypic Ratio)
This question asks us to match different types of genetic crosses with their characteristic phenotypic ratios. The key is to recall the expected ratios for Mendelian inheritance, incomplete dominance, and test crosses, leading to the correct option (C).
Understanding phenotypic ratios is fundamental to genetics. A phenotypic ratio describes the proportion of observable traits (phenotypes) among the offspring of a genetic cross. These ratios are determined by the type of inheritance (e.g., complete dominance, incomplete dominance) and the specific cross being performed.
Let's break down each type of cross and its expected phenotypic ratio.
1. Mendelian Monohybrid Cross (F2 Generation)
A Mendelian monohybrid cross involves tracking the inheritance of a single trait where one allele is completely dominant over the other. When two heterozygous individuals (F1 generation) are crossed, the F2 generation exhibits a characteristic phenotypic ratio.
- Concept: Consider a trait like pea plant height, where 'T' (tall) is dominant over 't' (dwarf). If we cross true-breeding tall (TT) with true-breeding dwarf (tt) plants, the F1 generation will all be heterozygous tall (Tt). When these F1 individuals are self-pollinated or crossed with each other (Tt x Tt), the offspring genotypes will be 1 TT : 2 Tt : 1 tt.
- Phenotypic Ratio: Due to complete dominance, both TT and Tt genotypes express the tall phenotype. Only tt expresses the dwarf phenotype. Therefore, the phenotypic ratio in the F2 generation is 3 Tall : 1 Dwarf.
- Match: This corresponds to (iii) 3 : 1 (F2).
2. Mendelian Dihybrid Cross (F2 Generation)
A Mendelian dihybrid cross involves tracking the inheritance of two different traits simultaneously, assuming independent assortment and complete dominance for each trait.
- Concept: Consider two traits, seed shape (R = round, r = wrinkled) and seed color (Y = yellow, y = green). If we cross true-breeding round, yellow (RRYY) with true-breeding wrinkled, green (rryy) plants, the F1 generation will all be heterozygous for both traits (RrYy). When these F1 individuals are self-pollinated or crossed with each other (RrYy x RrYy), the F2 generation will show a specific phenotypic distribution.
- Phenotypic Ratio: According to Mendel's Law of Independent Assortment, the alleles for different traits segregate independently. This results in a phenotypic ratio of 9 Round, Yellow : 3 Round, Green : 3 Wrinkled, Yellow : 1 Wrinkled, Green.
- Match: This corresponds to (iv) 9 : 3 : 3 : 1 (F2).
3. Incomplete Dominance (F2 Generation)
Incomplete dominance is a type of inheritance where neither allele is completely dominant over the other, resulting in a heterozygous phenotype that is intermediate between the two homozygous phenotypes.
- Concept: A classic example is flower color in snapdragons, where 'R' (red) and 'W' (white) alleles result in 'RW' (pink) heterozygotes. If we cross true-breeding red (RR) with true-breeding white (WW) flowers, the F1 generation will all be pink (RW). When these F1 individuals are self-pollinated or crossed with each other (RW x RW), the offspring genotypes will be 1 RR : 2 RW : 1 WW.
- Phenotypic Ratio: Because the heterozygous phenotype (pink) is distinct from both homozygous phenotypes (red and white), the genotypic ratio directly translates into the phenotypic ratio. Thus, the F2 phenotypic ratio is 1 Red : 2 Pink : 1 White.
- Match: This corresponds to (i) 1 : 2 : 1 (F2).
4. Test Cross (Monohybrid)
A test cross is a specific type of cross used to determine the genotype of an individual expressing a dominant phenotype. This is done by crossing the individual with a homozygous recessive individual.
- Concept: Suppose we have a pea plant that is tall (dominant phenotype), but we don't know if its genotype is homozygous dominant (TT) or heterozygous (Tt). We cross this plant with a homozygous recessive dwarf plant (tt).
- Case 1: If the tall parent is homozygous dominant (TT x tt): All offspring will be Tt (tall). The phenotypic ratio would be 1 Tall : 0 Dwarf.
- Case 2: If the tall parent is heterozygous (Tt x tt): The offspring will be 1 Tt : 1 tt. Phenotypically, this means 1 Tall : 1 Dwarf.
- Phenotypic Ratio: The question implies the classic outcome of a test cross used to reveal heterozygosity, which yields a 1:1 ratio. If the unknown dominant individual is heterozygous, the test cross will produce offspring in a 1:1 phenotypic ratio.
- Match: This corresponds to (ii) 1 : 1.
Summary of Matches:
- Mendelian monohybrid (F2) → (iii) 3 : 1
- Mendelian dihybrid (F2) → (iv) 9 : 3 : 3 : 1
- Incomplete dominance (F2) → (i) 1 : 2 : 1
- Test cross (monohybrid) → (ii) 1 : 1
Comparing these matches with the given options:
(A) 1–(ii), 2–(iv), 3–(i), 4–(iii)
(B) 1–(iii), 2–(i), 3–(iv), 4–(ii)
(C) 1–(iii), 2–(iv), 3–(i), 4–(ii)
(D) 1–(ii), 2–(i), 3–(iv), 4–(iii)
The correct option is (C).
The correctly matched option is (C), where 1–(iii), 2–(iv), 3–(i), and 4–(ii) are paired.
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