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Q.(a) Write IUPAC names of the following coordination compounds :

(i) [CoCl2(en)2]SO4[CoCl_2(en)_2]SO_4
(ii) K3[Fe(C2O4)3]K_3[Fe(C_2O_4)_3]
(OR)
(b) Differentiate between :
(i) Double salt and Complex compound
(ii) Didentate ligand and Ambidentate ligand
CBSECBSE Class XII Board 2025Subjective· 2mImportance★★★★★
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Part (a): (i) Dichloridobis(ethane-1,2-diamine)cobalt(III) sulphate; (ii) Potassium trioxalatoferrate(III). Part (b): double salts dissociate fully into simple ions while complexes keep their complex ion; a didentate ligand binds through two donor atoms simultaneously (chelate) whereas an ambidentate ligand can bind through either of two different atoms, one at a time.

Rules: name the cation before the anion; within brackets name ligands alphabetically (ignoring multiplying prefixes), then the metal with its oxidation state in Roman numerals; an anionic complex takes the suffix -ate.

(i) [CoCl2(en)2]SO4[CoCl_2(en)_2]SO_4. Cation =[CoCl2(en)2]+=[CoCl_2(en)_2]^+, anion =SO42−=SO_4^{2-}. Ligands: two chlorido (Cl−Cl^-) and two ethane-1,2-diamine (enen, neutral). Alphabetically "chlorido" precedes "ethane-1,2-diamine"; because "ethane-1,2-diamine" already contains a numeral, use bis. Oxidation state: x+2(−1)+2(0)=+1⇒x=+3x+2(-1)+2(0)=+1\Rightarrow x=+3.

-> Dichloridobis(ethane-1,2-diamine)cobalt(III) sulphate.

(ii) K3[Fe(C2O4)3]K_3[Fe(C_2O_4)_3]. Cation =K+=K^+, anion =[Fe(C2O4)3]3−=[Fe(C_2O_4)_3]^{3-}. Ligand oxalato (C2O42−C_2O_4^{2-}) x3 = trioxalato. Oxidation state: x+3(−2)=−3⇒x=+3x+3(-2)=-3\Rightarrow x=+3. The complex is anionic, so iron becomes ferrate.

-> Potassium trioxalatoferrate(III).

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