Q.Give an example of a solid solution in which the solute is a gas.
Concept understanding — Types Of Solutions
Types of Solutions: From Everyday Life to Chemistry
You already know what a solution is — sugar dissolved in water, salt in water, even the air you breathe. But not all solutions behave the same way. Some dissolve easily, some refuse to dissolve beyond a point, and some can hold more solute than they normally should. That difference is what we classify as types of solutions based on how much solute is dissolved.
The Intuition: A Cup of Tea
Imagine making a cup of tea. You add one spoon of sugar — it dissolves completely. You add a second spoon — still dissolves. A third spoon — maybe it dissolves, maybe it doesn't. At some point, no matter how much you stir, the sugar just sits at the bottom.
That moment — when no more sugar dissolves — is the saturation point. Before that, you have an unsaturated solution. At that exact point, you have a saturated solution. And if you carefully heat the tea, dissolve more sugar, then cool it down without disturbing it — you might get a supersaturated solution, where more sugar stays dissolved than should be possible at that temperature.
That's the entire idea. Three types, defined by how much solute is dissolved relative to the maximum possible.
The Precise Statement
A solution is a homogeneous mixture of a solute (the substance being dissolved) and a solvent (the substance doing the dissolving). Based on the amount of solute dissolved relative to its solubility at a given temperature, solutions are classified into three types:
Types of Solutions (by saturation)
- Unsaturated solution — contains less solute than the maximum that can be dissolved at that temperature.
- Saturated solution — contains exactly the maximum amount of solute that can be dissolved at that temperature.
- Supersaturated solution — contains more solute than the maximum normally possible at that temperature (a metastable state).
Breaking Down Each Type
Unsaturated solution — the most common type. You can still add more solute and it will dissolve. The concentration is below the solubility limit. If you have a glass of water at room temperature and add a pinch of salt, you get an unsaturated solution. Add more salt — still unsaturated, until you hit the limit.
Saturated solution — the solute and undissolved solute are in dynamic equilibrium. At the molecular level, the rate at which solute particles dissolve equals the rate at which they crystallize out. No net change. If you keep adding salt to water and it stops dissolving, the liquid above the undissolved salt is a saturated solution. The concentration is fixed at the solubility value for that temperature.
A common mistake: thinking a saturated solution is always "thick" or "concentrated." Not true. Saturation depends on the solute's solubility. Lead(II) chloride saturates at about 0.45 g per 100 mL water — that's a very dilute saturated solution. Saturation ≠ high concentration.
Supersaturated solution — this is a tricky one. You create it by heating the solvent, dissolving more solute than normally possible, then carefully cooling it. The excess solute stays dissolved because there's no nucleation site (no scratch, no dust particle) to trigger crystallization. It's unstable — the slightest disturbance (a dust speck, a scratch on the glass, even a sudden jolt) causes the excess solute to crystallize out instantly.
Supersaturated solutions are the reason "hot ice" (sodium acetate) hand warmers work. You click a metal disc inside, which creates a nucleation site, and the entire solution crystallizes in seconds, releasing heat.
A Quick Comparison
| Type | Solute amount vs. solubility | Can more solute dissolve? | Stability |
|---|---|---|---|
| Unsaturated | Less than maximum | Yes | Stable |
| Saturated | Equal to maximum | No (at equilibrium) | Stable |
| Supersaturated | More than maximum | No (excess will crystallize) | Metastable |
Why This Matters
In exams, you'll often be asked to identify the type of solution from a given scenario — like "50 g of salt dissolved in 100 g water at 30°C, given solubility is 36 g per 100 g water." That's a supersaturated solution (50 > 36). Or you might be asked what happens when you add a seed crystal to a supersaturated solution — it triggers crystallization.
The key is always: compare the actual amount dissolved to the solubility at that temperature. That single comparison gives you the type.
Solubility is temperature-dependent. A solution that is saturated at 20°C becomes unsaturated if heated to 50°C (because solubility usually increases with temperature). Always check the temperature condition given in the problem.
Searches such as "types of solutions saturated unsaturated supersaturated" and "solutions class 12 chemistry notes" align directly with the Solutions chapter of the NCERT/CBSE Class 12 Chemistry curriculum. Identifying which type a given scenario describes is a common short-answer question in board exams.
Why this formula?
Types of Solutions: Why the Key Formulae Hold
Understanding why the formulae work is essential for Indian exams (JEE, NEET, CBSE). Let's break down the reasoning behind the most important relationships.
1. The Basic Classification: What Makes a Solution?
A solution is a homogeneous mixture of two or more substances. The key idea is intermolecular forces between solute and solvent particles.
- Ideal Solution: Solute-solvent interactions are identical to solute-solute and solvent-solvent interactions. Why? No net energy change on mixing — the molecules "fit" perfectly.
- Non-Ideal Solution: Interactions differ, leading to deviation from Raoult's law.
2. Raoult's Law: The Foundation
Formula:
Psolution=xsolvent⋅Psolvent0
Why does this hold?
Imagine a pure solvent surface. The vapour pressure P0 comes from molecules escaping the liquid. When you add a non-volatile solute, solute molecules occupy some surface area, blocking solvent molecules from escaping.
- The fraction of surface available to solvent = mole fraction of solvent (xsolvent).
- Therefore, the rate of escape (vapour pressure) is proportional to that fraction:
Psolution∝xsolvent
- At the limit xsolvent=1, Psolution=P0, so the constant is P0.
Key insight: Raoult's law is a surface-area argument, not a volume argument.
3. Relative Lowering of Vapour Pressure
Formula:
P0P0−P=xsolute
Derivation in one line:
From Raoult's law:
P=xsolvent⋅P0
Since xsolvent+xsolute=1,
P=(1−xsolute)P0
⇒P0−P=xsolute⋅P0
⇒P0P0−P=xsolute
Why is this useful?
It depends only on the mole fraction of solute, not on its identity — making it a colligative property.
4. Elevation of Boiling Point
Formula:
ΔTb=Kb⋅m
Why does boiling point rise?
- Boiling occurs when vapour pressure = atmospheric pressure.
- Adding a non-volatile solute lowers vapour pressure (Raoult's law).
- To reach atmospheric pressure again, you must raise the temperature.
- The shift ΔTb is proportional to the molality m (moles of solute per kg of solvent), because:
- More solute → greater vapour pressure lowering → more temperature needed.
- Kb (ebullioscopic constant) is a property of the solvent only.
5. Depression of Freezing Point
Formula:
ΔTf=Kf⋅m
Why does freezing point drop?
- At the freezing point, solid and liquid solvent are in equilibrium.
- Adding solute disrupts this equilibrium — solute molecules interfere with the orderly crystal formation of the solvent.
- To re-establish equilibrium, you must lower the temperature.
- Again, ΔTf∝m, and Kf depends only on the solvent.
Common exam trap: Both ΔTb and ΔTf are colligative — they depend on number of solute particles, not their nature.
6. Osmotic Pressure
Formula:
Π=i⋅C⋅R⋅T
Why does this hold?
- Osmosis is the net movement of solvent from low solute concentration to high solute concentration across a semipermeable membrane.
- The solvent moves to dilute the higher concentration — this is a entropy-driven process (mixing increases disorder).
- Osmotic pressure Π is the external pressure needed to stop this flow.
- It behaves like an ideal gas law for solute particles:
ΠV=nRT⇒Π=VnRT=CRT
- The van't Hoff factor i accounts for dissociation/association of solute (e.g., NaCl gives i≈2).
7. The van't Hoff Factor i
Formula:
i=expected colligative propertyobserved colligative property
Why is i needed?
- Colligative properties depend on number of particles.
- If a solute dissociates (e.g., NaCl→Na++Cl−), the effective particle count doubles.
- If it associates (e.g., benzoic acid in benzene forms dimers), the count halves.
- i corrects for this:
ΔTf=i⋅Kf⋅m
Quick Summary Table
| Property | Formula | Why it works |
|---|---|---|
| Raoult's law | P=xsolventP0 | Surface area blocking by solute |
| Relative lowering | P0ΔP=xsolute | Direct algebraic consequence |
| Boiling point elevation | ΔTb=Kbm | Need higher temp to overcome vapour pressure drop |
| Freezing point depression | ΔTf=Kfm | Solute disrupts crystal formation |
| Osmotic pressure | Π=iCRT | Analogy to ideal gas law for solute particles |
Final takeaway: Every formula in "Types of Solutions" flows from Raoult's law (for vapour pressure) and the particle-counting principle (for colligative properties). Understand these two roots, and you can reconstruct the rest.
Solid Solution with Gaseous Solute
A solid solution forms when one substance dissolves uniformly in another at the atomic or molecular level, creating a homogeneous single-phase system.
When a gas dissolves in a solid, the gas molecules occupy interstitial spaces (gaps between atoms) in the solid's crystal lattice. The classic and most important example is hydrogen in palladium.
Palladium metal has a face-centered cubic structure with small voids between metal atoms. Hydrogen gas molecules dissociate into atomic hydrogen at the palladium surface, and these H atoms diffuse into the interstitial sites of the palladium lattice. The result is a homogeneous solid solution where palladium can absorb up to 900 times its own volume of hydrogen gas.
This property makes palladium useful in hydrogen purification and storage applications.
An example of a solid solution with a gaseous solute is hydrogen dissolved in palladium metal (Pd-H system).
When a gas dissolves into a solid matrix and forms a homogeneous mixture at the molecular level, we get a solid solution with a gaseous solute. Hydrogen in palladium is the classic example.
Understanding Solid Solutions with Gaseous Solutes
A solution doesn't have to be liquid. Any homogeneous mixture where one substance (the solute) is uniformly dispersed in another (the solvent) at the molecular or atomic scale qualifies as a solution, regardless of the final state of matter.
When we talk about a solid solution with a gas as the solute, we mean that gas molecules or atoms have been absorbed into the crystal lattice of a solid and distributed uniformly throughout. The gas doesn't just sit on the surface or in visible pockets—it occupies interstitial spaces (gaps between atoms) or substitutional sites in the solid's structure.
The Classic Example: Hydrogen in Palladium
The most important and widely cited example is palladium metal absorbing hydrogen gas.
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The absorption process: When palladium (Pd) is exposed to hydrogen gas (HX2), the metal has a remarkable ability to absorb large quantities of it. The hydrogen molecules dissociate into individual hydrogen atoms at the palladium surface.
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Formation of the solid solution: These hydrogen atoms then diffuse into the palladium crystal lattice, occupying the octahedral interstitial sites—the small spaces between the palladium atoms. At room temperature, palladium can absorb up to 900 times its own volume of hydrogen gas.
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Homogeneity: The hydrogen atoms distribute themselves uniformly throughout the palladium structure, creating a true solid solution. The resulting material is often written as PdHXx, where x can vary depending on temperature and pressure.
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Why this matters: This property makes palladium extremely useful for hydrogen storage, purification (palladium membranes selectively allow hydrogen to pass through), and catalysis. The hydrogen can be released by heating or reducing the pressure.
Other metals also form solid solutions with hydrogen, including platinum, nickel, and certain alloys. However, palladium's capacity and reversibility make it the textbook example.
Other Examples
While hydrogen in palladium is the standard answer, you might also encounter:
- Hydrogen in platinum (Pt)
- Hydrogen in titanium (Ti) or zirconium (Zr)—these form metal hydrides that can be considered solid solutions at certain compositions
The key feature in all cases is that the gas atoms become part of the solid's structure, not merely trapped in voids or adsorbed on the surface.
The classic example of a solid solution in which the solute is a gas is hydrogen gas dissolved in palladium metal (forming PdHXx).
Method: Classification by Physical State of Solute and Solvent
This method uses the physical states (solid, liquid, gas) of both components to identify the type of solution.
Steps
- Identify the solvent — the component present in larger amount (the medium).
- Identify the solute — the component present in smaller amount (dissolved substance).
- Check the physical state of each at room temperature.
- Classify the solution based on the combination of states.
Example: Solid solution with gaseous solute
Solute: Gas
Solvent: Solid
Real example: Hydrogen gas (H2) dissolved in palladium metal (Pd)
- Solvent: Palladium (solid metal)
- Solute: Hydrogen gas
- Result: A solid solution where gas molecules occupy interstitial spaces in the metal lattice.
Key point: This is possible because palladium can absorb large volumes of hydrogen gas into its crystal structure, forming a homogeneous solid solution.
Other common examples:
- Helium gas dissolved in platinum
- Hydrogen dissolved in nickel
Quick Reference Table
| Solute | Solvent | Solution Type | Example |
|---|---|---|---|
| Gas | Solid | Solid solution | H2 in Pd |
| Gas | Liquid | Liquid solution | CO2 in water (soda) |
| Gas | Gas | Gaseous solution | Air (O2 + N2) |
Final answer: A solid solution with a gaseous solute is hydrogen gas dissolved in palladium metal.
Common Mistakes: Solid Solutions with a Gaseous Solute
Students often struggle with this concept because it challenges the everyday intuition that "solids can't dissolve gases." Here are the most frequent errors and how to avoid them.
✗ Mistake 1: Confusing "solute" with "solvent"
The error: Students list examples like "air" (gas in gas) or "salt water" (solid in liquid) — these are not solid solutions at all.
Why it happens: The phrase "solid solution" is misinterpreted as "a solution that is solid" rather than "a solution where the solvent is solid."
How to avoid: Always identify the solvent first. In a solid solution, the solvent (the majority component) must be a solid. The solute can be a gas, liquid, or another solid.
Key rule: Solid solution = solid solvent + any solute (gas, liquid, or solid).
✗ Mistake 2: Giving impossible examples
The error: Students write "ice cubes in air" or "sugar in a gas" — these are not solutions at all.
Why it happens: Lack of clarity about what constitutes a true solution (homogeneous mixture at molecular level).
How to avoid: Remember that a true solution is homogeneous. For a gas to dissolve in a solid, the gas molecules must fit into the interstitial spaces or lattice vacancies of the solid.
✗ Mistake 3: Forgetting the correct example
The error: Students cannot recall any valid example under exam pressure.
Why it happens: The only common example is specialized — hydrogen in palladium or hydrogen in platinum.
How to avoid: Memorise this one key example:
Correct answer: Hydrogen gas dissolved in palladium metal
(Palladium metal absorbs up to 900 times its own volume of hydrogen gas, forming a homogeneous solid solution.)
✓ Quick Reference Table
| Component | Example | Valid? |
|---|---|---|
| Gas in solid | H2 in Pd | ✓ Yes |
| Gas in solid | O2 in Pt | ✓ Yes |
| Gas in solid | Air in ice | ✗ No (not homogeneous) |
| Gas in solid | CO2 in solid water | ✗ No (forms clathrate, not true solution) |
📝 Exam Tip
If asked to "give an example," write:
"Hydrogen gas (H2) dissolved in palladium metal (Pd) — a solid solution where the solute is a gas and the solvent is a solid."
This shows you understand both the concept and the terminology.
Showing the 12 most recent of 24 on this concept.
- CBSE 2026Set 56/3/11 markMCQQ.The boiling point of an azeotropic mixture of water and ethanol is less than that of pure water and ethanol. The mixture shows : (A) positive deviation from Raoult's Law. (B) negative deviation from Raoult's Law. (C) no deviation from Raoult's Law. (D) that the solution is an ideal solution.
›Reveal solutionSolution
A mixture with a boiling point lower than its pure components is a minimum boiling azeotrope, which occurs when the solution exhibits positive deviation from Raoult's Law due to higher vapor pressure.
When we talk about solutions, especially liquid-liquid mixtures, their behavior is often described relative to Raoult's Law. This law provides a baseline for ideal solutions, and deviations from it tell us about the intermolecular interactions within the mixture.
Understanding Raoult's Law and Deviations
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Raoult's Law: For an ideal solution, the partial vapor pressure of each volatile component in the solution is directly proportional to its mole fraction in the solution and the vapor pressure of the pure component.
PA=xAPA∘
PB=xBPB∘
Where PA and PB are the partial vapor pressures of components A and B in the solution, xA and xB are their respective mole fractions, and PA∘ and PB∘ are the vapor pressures of the pure components.
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Ideal Solutions: These solutions perfectly obey Raoult's Law over the entire range of concentrations. In an ideal solution, the intermolecular forces between A-A, B-B, and A-B molecules are all very similar.
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Non-Ideal Solutions: Most real solutions do not behave ideally and show deviations from Raoult's Law. These deviations arise from differences in intermolecular forces.
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Positive Deviation: This occurs when the intermolecular forces between A-B molecules are weaker than the average of A-A and B-B forces. This makes it easier for molecules to escape into the vapor phase, leading to a higher vapor pressure than predicted by Raoult's Law.
PA>xAPA∘ and PB>xBPB∘.
Examples: Ethanol-water, acetone-carbon disulfide.
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Negative Deviation: This occurs when the intermolecular forces between A-B molecules are stronger than the average of A-A and B-B forces. This makes it harder for molecules to escape into the vapor phase, leading to a lower vapor pressure than predicted by Raoult's Law.
PA<xAPA∘ and PB<xBPB∘.
Examples: Acetone-chloroform, nitric acid-water.
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Connecting Vapor Pressure to Boiling Point
The boiling point of a liquid is the temperature at which its vapor pressure equals the external atmospheric pressure.
- If a solution has a higher vapor pressure at a given temperature, it will reach the atmospheric pressure at a lower temperature. Thus, a higher vapor pressure corresponds to a lower boiling point.
- Conversely, if a solution has a lower vapor pressure, it will require a higher temperature to reach atmospheric pressure. Thus, a lower vapor pressure corresponds to a higher boiling point.
Azeotropes
Azeotropes are constant boiling mixtures that distill without change in composition. They are a specific type of non-ideal solution.
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Minimum Boiling Azeotropes: These are formed by solutions showing positive deviation from Raoult's Law. At a specific composition, the solution has a vapor pressure higher than either pure component, leading to a boiling point lower than either pure component. The ethanol-water mixture is a classic example. Pure ethanol boils at 78.4∘C, pure water boils at 100∘C, but their azeotrope (approximately 95.6% ethanol by mass) boils at 78.2∘C.
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Maximum Boiling Azeotropes: These are formed by solutions showing negative deviation from Raoult's Law. At a specific composition, the solution has a vapor pressure lower than either pure component, leading to a boiling point higher than either pure component. For example, the nitric acid-water azeotrope boils at 120.5∘C, which is higher than pure nitric acid (83∘C) and pure water (100∘C).
Step-by-step Solution
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Analyze the given information: The problem states that the boiling point of the azeotropic mixture of water and ethanol is less than that of pure water and pure ethanol.
- Boiling point of mixture < Boiling point of pure water
- Boiling point of mixture < Boiling point of pure ethanol
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Relate boiling point to vapor pressure: A lower boiling point implies that the mixture has a higher vapor pressure compared to its pure components at the same temperature. This is because less energy (lower temperature) is needed for its vapor pressure to reach the external atmospheric pressure.
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Connect higher vapor pressure to Raoult's Law deviation: When a solution exhibits a vapor pressure higher than what would be predicted by Raoult's Law for an ideal solution, it is said to show positive deviation from Raoult's Law. This is characteristic of minimum boiling azeotropes.
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Conclusion: Since the ethanol-water azeotrope has a boiling point lower than its pure components, it is a minimum boiling azeotrope, which is a direct consequence of showing positive deviation from Raoult's Law.
Watch outDo not confuse the boiling point of the azeotrope with the boiling points of the pure components. A minimum boiling azeotrope has a boiling point lower than both pure components, not just lower than one of them.
The mixture shows positive deviation from Raoult's Law.
✓Final answerThe mixture shows (A) positive deviation from Raoult's Law.
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- CBSE 2026Set 56/1/11 markMCQQ.Assertion (A) : It is not possible to separate the components of an azeotrope by fractional distillation. Reason (R) : Components of an azeotrope have the same composition in liquid and vapour phase and boil at a constant temperature. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true.
›Reveal solutionSolution
An azeotrope is a constant-boiling mixture whose vapour has the same composition as the liquid, making separation by simple fractional distillation impossible. Both the assertion and the reason are true, and the reason correctly explains the assertion.
Concept and Intuition
Fractional distillation works because, for most liquid mixtures, the vapour is richer in the more volatile component. As you boil the mixture, the vapour is condensed and reboiled repeatedly, gradually enriching the distillate in the lower-boiling component. This process relies on a difference in composition between the liquid and vapour phases at equilibrium.
An azeotrope is a special mixture that defies this. At a specific composition (the azeotropic composition), the liquid and vapour have exactly the same mole fractions. The mixture boils at a constant temperature — either higher or lower than the boiling points of the pure components — and the vapour that comes off is identical in composition to the liquid left behind. No amount of distillation can change the composition of either phase; the mixture simply boils away unchanged.
Therefore, the reason (R) correctly states the defining property of an azeotrope, and the assertion (A) correctly states the consequence: you cannot separate the components by fractional distillation.
Step-by-step reasoning
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Understand the assertion.
Assertion (A) says: “It is not possible to separate the components of an azeotrope by fractional distillation.” This is a well-known fact in chemistry. For example, ethanol and water form a minimum-boiling azeotrope at about 95.6% ethanol by mass. If you try to distill a mixture that is already at that composition, the distillate will also be 95.6% ethanol — you cannot get pure ethanol by simple fractional distillation.
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Understand the reason.
Reason (R) says: “Components of an azeotrope have the same composition in liquid and vapour phase and boil at a constant temperature.” This is the precise definition of an azeotrope. At the azeotropic point, the boiling point is either a maximum or a minimum, and the vapour-liquid equilibrium curve touches the diagonal line (where xliquid=yvapour). Because the compositions are equal, there is no driving force for separation by distillation.
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Check if the reason correctly explains the assertion.
The reason directly explains why fractional distillation fails: if the vapour has the same composition as the liquid, then no enrichment occurs during boiling or condensation. The constant boiling temperature is a consequence of this fixed composition. Thus, the reason is the correct explanation for the assertion.
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Evaluate the options.
- Option (A): Both true, and (R) is the correct explanation of (A). This matches our analysis.
- Option (B): Both true, but (R) is not the correct explanation — this is false because (R) directly explains (A).
- Option (C): (A) true, (R) false — false because (R) is true.
- Option (D): (A) false, (R) true — false because (A) is true.
Watch outA common mistake is to think that azeotropes can be separated by simple distillation if you change the pressure. While pressure-swing distillation can sometimes break an azeotrope, the question specifically says “fractional distillation” under ordinary conditions. At a given pressure, the azeotropic composition is invariant, so fractional distillation alone cannot separate the components.
✓Final answerThe correct option is (A) — both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).
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- CBSE 2026Set ANNUAL1 markQ.Write the solute and solvent in the gaseous solution of chloroform in nitrogen gas.
›Reveal solutionSolution
In any solution, the component present in a larger proportion is the solvent, and the one present in a smaller proportion is the solute - this also applies to gas-in-gas solutions.
In a gaseous solution of chloroform vapour in nitrogen gas, nitrogen (the bulk carrier gas) is the solvent, and chloroform (present in a smaller, dilute amount) is the solute.
✓Final answerSolute: chloroform; Solvent: nitrogen gas.
- CBSE 2026Set ANNUAL1 markMCQQ.Which of the following is the correct example of a solid solution in which the solute is in gas phase?(a) Copper dissolved in gold(b) Camphor in nitrogen gas(c) Hydrogen in palladium(d) All of the above
›Reveal solutionSolution
Solid solutions are classified by the physical state of the solute dissolved in the solid solvent; hydrogen dissolved in solid palladium is the classic gas-in-solid example.
A solid solution can have solute particles that are themselves solid, liquid, or gaseous, dispersed uniformly in a solid solvent.
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Copper dissolved in gold — both are solids, so this is a solid-in-solid solution (an alloy).
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Camphor in nitrogen gas — this is actually a solid dissolved in a gas (or, read the other way, describes a gas as solvent), not a solid solution with a gaseous solute.
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Hydrogen in palladium — hydrogen gas molecules occupy interstitial spaces within the solid palladium lattice. Here the solvent is solid (Pd) and the solute is a gas (H₂). This is the standard NCERT example of a solid solution in which the solute is in the gas phase.
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Hence "All of the above" is incorrect since only one option actually fits the gas-in-solid description.
✓Final answer(c) Hydrogen in palladium — this is a solid solution of a gas (solute) dissolved in a solid (solvent).
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- CBSE 2026Set ANNUAL1 markMCQQ.The carbonated water is an example of _____.(a) solid in liquid solution(b) liquid in liquid solution(c) gas in liquid solution(d) liquid in gas solution
›Reveal solutionSolution
Carbonated water is CO2 gas dissolved in water — a gas-in-liquid solution.
Carbonated water is prepared by dissolving carbon dioxide gas (CO2) under pressure in water. Here the solute (CO2) is a gas and the solvent (water) is a liquid, so carbonated water is a classic example of a gas-in-liquid solution.
✓Final answer(c) gas in liquid solution.
- CBSE 2025Set 56/6/11 markMCQQ.A solution of acetone in ethanol : (A) obeys Raoult's law. (B) forms an ideal solution. (C) shows a positive deviation from Raoult's law. (D) shows a negative deviation from Raoult's law.
›Reveal solutionSolution
Acetone–ethanol mixtures form hydrogen bonds weaker than those in pure ethanol, making escape easier and raising vapor pressure above the ideal prediction. The solution shows a positive deviation from Raoult's law — option (C).
Types of Solutions: Understanding Deviations from Ideality
Raoult's law predicts that the partial vapor pressure of each component in a solution is proportional to its mole fraction: Pi=xiPi0. This holds perfectly only for ideal solutions, where the intermolecular forces between unlike molecules (A–B) are identical in strength to those between like molecules (A–A and B–B). When these forces differ, the solution deviates from Raoult's law.
Positive deviation occurs when A–B interactions are weaker than the average of A–A and B–B interactions. Molecules escape more easily into the vapor phase, so the total vapor pressure exceeds the ideal prediction.
Negative deviation occurs when A–B interactions are stronger than those in the pure components. Molecules are held more tightly in the liquid, reducing vapor pressure below the ideal value.
The key is to compare the intermolecular forces in the mixture with those in the pure liquids.
Step-by-Step Analysis
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Identify the intermolecular forces in pure ethanol
Ethanol (CX2HX5OH) has a hydroxyl group that forms strong hydrogen bonds between molecules. These O–H···O interactions are quite robust, holding ethanol molecules together tightly in the liquid phase.
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Identify the intermolecular forces in pure acetone
Acetone (CHX3COCHX3) is a polar molecule with a carbonyl group, but it cannot donate hydrogen bonds (no O–H or N–H). It can only accept hydrogen bonds. In pure acetone, the dominant forces are dipole–dipole interactions, which are weaker than hydrogen bonds.
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Examine the acetone–ethanol interaction
When acetone and ethanol mix, ethanol can donate a hydrogen bond to the oxygen of acetone's carbonyl group, forming an O–H···O=C interaction. However, this hydrogen bond is weaker than the O–H···O–H hydrogen bonds present in pure ethanol, because the carbonyl oxygen is a less effective hydrogen-bond acceptor than the hydroxyl oxygen.
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Compare net intermolecular forces
- In pure ethanol: strong H-bonds (O–H···O–H)
- In the mixture: weaker H-bonds (O–H···O=C) plus dipole–dipole forces
- The average A–B interaction is weaker than the ethanol–ethanol interaction.
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Predict the deviation
Because the unlike interactions (acetone–ethanol) are weaker than the average of the like interactions (especially the strong ethanol–ethanol H-bonds), molecules in the mixture are held less tightly. They escape into the vapor phase more readily, raising the vapor pressure above what Raoult's law predicts.
Watch outA common mistake is to assume that any hydrogen bonding between components means negative deviation. The critical question is whether the new H-bonds are stronger or weaker than those in the pure liquids. Here, acetone–ethanol H-bonds are weaker than ethanol–ethanol H-bonds.
Experimental Evidence
The acetone–ethanol system is a textbook example of positive deviation. The total vapor pressure of the mixture is higher than the ideal value at all compositions, and the system forms a minimum-boiling azeotrope (a hallmark of positive deviation).
✓Final answerThe correct option is (C) — the solution shows a positive deviation from Raoult's law.
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- CBSE 2025Set X11 markMCQQ.Camphor in nitrogen gas, is an example of ______.(a) liquid solution(b) solid solution(c) gaseous solution(d) aqueous solution
›Reveal solutionSolution
Solvent = nitrogen gas, solute = solid camphor → a solid-in-gas solution, classified as a gaseous solution.
A solution is classified by the physical state of the solvent (the component present in larger amount / the medium). Here the medium is nitrogen gas, so the solution is a gaseous solution, with solid camphor as the solute dispersed in it.
This is the standard NCERT example of a solid solute in a gaseous solvent:
Solute Solvent Type Example solid gas gaseous solution camphor in nitrogen gas ✓Final answer(c) gaseous solution
- CBSE 2025Set JZ1 markMCQQ.Give an example of such solid solution in which solute is gas.(a) Oxygen dissolved in water.(b) Solution of camphor in nitrogen.(c) Solution of hydrogen in palladium.(d) Glucose dissolved in water.
›Reveal solutionSolution
A solid solvent holding a gaseous solute → hydrogen dissolved in palladium, option (c).
Concept. A solution is a homogeneous mixture; it is classified by the physical state of the solvent (the component in excess), and separately by the state of the solute. A solid solution therefore has a solid as its solvent. The question asks for a solid solution in which the solute is a gas.
Checking the options:
- (a) Oxygen (gas) in water (liquid) → this is a liquid solution, not solid.
- (b) Camphor (solid) in nitrogen (gas) → solvent is a gas, so this is a gaseous solution.
- (c) Hydrogen (gas) in palladium (solid) → solvent is solid, solute is gas → a solid solution with a gaseous solute. Palladium famously occludes large volumes of H2 in the interstitial spaces of its lattice.
- (d) Glucose (solid) in water (liquid) → a liquid solution.
Only (c) has a solid solvent and a gaseous solute.
✓Final answer(c) Solution of hydrogen in palladium — a solid (Pd) solvent with a gaseous (H2) solute.
- CBSE 2025Set A1 markMCQQ.Homogeneous mixtures of two or more than two components is —(a) Solution(b) Liquid solute(c) Liquid solvent(d) Solvent
›Reveal solutionSolution
A solution is a homogeneous mixture of two or more non-reacting substances.
A mixture is homogeneous when its composition and properties are uniform throughout — no individual component can be distinguished by eye, and any sample taken from any part of it is identical. A solution (made of a solute dissolved in a solvent) is exactly this kind of mixture. Options (b) 'liquid solute', (c) 'liquid solvent' and (d) 'solvent' each name only ONE ingredient of a solution, not the mixture as a whole, so none of them can be the definition being asked for.
✓Final answer(a) Solution — the homogeneous mixture of two or more components.
- CBSE 2024Set 56/2/11 markMCQQ.An azeotropic solution of two liquids has boiling point lower than either of them when it : (A) is saturated (B) shows positive deviation from Raoult's law (C) shows negative deviation from Raoult's law (D) shows no deviation from Raoult's law
›Reveal solutionSolution
An azeotrope with a boiling point lower than either pure component forms when the mixture shows positive deviation from Raoult's law, because the components "want to escape" the liquid phase more readily than ideal behavior predicts. The answer is (B).
Understanding Azeotropes and Deviations from Ideality
An azeotrope is a constant-boiling mixture where the vapor has the same composition as the liquid. This means you cannot separate the components by simple distillation at that composition. The key to understanding which type of azeotrope forms lies in how the solution deviates from Raoult's law.
Raoult's law for an ideal solution states that the partial vapor pressure of each component is proportional to its mole fraction:
Pi=xiPi0
where Pi0 is the vapor pressure of the pure component. Real solutions often deviate from this ideal behavior due to intermolecular forces between unlike molecules differing from those between like molecules.
The Connection Between Deviation and Boiling Point
The boiling point of a liquid is reached when its total vapor pressure equals atmospheric pressure. If a mixture has a higher total vapor pressure than predicted by Raoult's law, it will boil at a lower temperature. Conversely, if the vapor pressure is lower than ideal, the boiling point rises.
Step-by-Step Analysis
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Positive Deviation from Raoult's Law
When A-B interactions are weaker than A-A and B-B interactions, molecules escape the liquid phase more easily than in an ideal solution. The total vapor pressure is:
Ptotal>xAPA0+xBPB0
This increased vapor pressure means the mixture reaches atmospheric pressure at a lower temperature than either pure component. The azeotrope formed is a minimum-boiling azeotrope.
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Negative Deviation from Raoult's Law
When A-B interactions are stronger than A-A and B-B interactions (hydrogen bonding, for example), molecules are held more tightly in the liquid phase:
Ptotal<xAPA0+xBPB0
The reduced vapor pressure means a higher boiling point than either pure component. This forms a maximum-boiling azeotrope.
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No Deviation (Ideal Solution)
An ideal solution follows Raoult's law exactly. No azeotrope forms because the vapor composition continuously changes with liquid composition during distillation. Complete separation is possible.
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Saturation
The term "saturated" refers to a solution containing the maximum amount of solute at a given temperature. This concept is unrelated to azeotrope formation or boiling point behavior.
TipA quick mnemonic: Positive deviation → Molecules repel → Higher vapor pressure → Lower boiling point. Think of ethanol-water (positive deviation, minimum-boiling azeotrope at 78.2°C, lower than water's 100°C).
Watch outDon't confuse the direction of deviation with the direction of boiling point change. Positive deviation (higher vapor pressure) gives a lower boiling point, which can seem counterintuitive at first.
Classic Examples
System Deviation Type Azeotrope Type Boiling Point Ethanol + Water Positive Minimum-boiling 78.2°C (lower than both) Acetone + Chloroform Negative Maximum-boiling Higher than both Nitric acid + Water Negative Maximum-boiling 120.5°C (higher than both) ✓Final answerThe correct option is (B) — an azeotropic solution has a boiling point lower than either component when it shows positive deviation from Raoult's law.
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- CBSE 2024Set ANNUAL1 markQ.Define saturated solution.
›Reveal solutionSolution
A saturated solution has reached the maximum solute concentration possible at that temperature; dissolution and crystallisation occur at equal rates.
When a solute is added to a solvent, it keeps dissolving until a point is reached where the solution can hold no additional solute (at a fixed temperature and pressure) - at this point a dynamic equilibrium is established between the solute molecules going into solution and those coming out of solution (if excess undissolved solute is present).
Such a solution, where the rate of dissolution equals the rate of crystallisation (precipitation), is called a saturated solution. Its concentration at that temperature equals the solubility of the solute in that solvent.
✓Final answerA saturated solution is one in which no more solute can dissolve at that temperature - the dissolved and undissolved solute are in dynamic equilibrium.
- CBSE 2024Set ANNUAL1 markQ.Write names of solute and solvent present in sodium amalgam solution.
›Reveal solutionSolution
Sodium amalgam is a solution of sodium metal dissolved in mercury; since mercury is present in the larger amount and is the medium, it is the solvent, while sodium (the dissolved component) is the solute.
An amalgam is an alloy/solution of a metal dissolved in mercury.
In sodium amalgam, solid sodium dissolves into liquid mercury; mercury, being the medium into which sodium is dissolved (and normally present in larger proportion), is the solvent, and sodium is the solute.
✓Final answerSolute: Sodium (Na); Solvent: Mercury (Hg).
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