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Exercises · 1.24

Q.Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3OHCH_3OH, CH3CNCH_3CN.

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Solubility in n-octane (a nonpolar solvent) increases with the nonpolar character of the solute. The order is: KCl < CH₃OH < CH₃CN < Cyclohexane. Cyclohexane is fully miscible; KCl is practically insoluble.

Why This Approach Works

The guiding principle here is "like dissolves like." n-Octane (C8H18\text{C}_8\text{H}_{18}) is a straight-chain alkane — a completely nonpolar, hydrocarbon solvent. It has no dipole moment and cannot form hydrogen bonds. For a solute to dissolve well in n-octane, its molecules must interact with the solvent primarily through London dispersion forces (weak temporary dipoles). Any strong polar or ionic interactions within the solute must be overcome by equally strong solute-solvent interactions — which n-octane simply cannot provide.

So, the more nonpolar a solute is, the more soluble it will be. The more polar or ionic it is, the less soluble.

Let’s examine each solute:

  1. KCl (Potassium chloride) — This is an ionic compound. In the solid state, it is held together by strong electrostatic forces (lattice energy). To dissolve, these ions must be separated and solvated. n-Octane, being nonpolar, cannot stabilize the separated ions at all. The energy cost to break the lattice is huge, and there is almost no energy gain from solvation. Result: practically insoluble.

  2. CH₃OH (Methanol) — Methanol has a polar –OH group capable of strong hydrogen bonding. The rest of the molecule is a tiny methyl group. While methanol can mix with water freely, in n-octane the hydrogen bonds between methanol molecules must be broken, and the polar –OH group has no affinity for the alkane chains. Only the small methyl group can interact weakly via dispersion forces. So methanol is poorly soluble, though slightly more than KCl because the energy cost to break its intermolecular bonds is lower than breaking an ionic lattice.

  3. CH₃CN (Acetonitrile) — Acetonitrile has a polar C≡N triple bond (a strong dipole), but the methyl group provides a small nonpolar region. The nitrile group is polar but cannot form strong hydrogen bonds like –OH can (it is a hydrogen bond acceptor, not a donor). Its intermolecular forces are dipole-dipole, which are weaker than the hydrogen bonds in methanol. This means less energy is required to separate acetonitrile molecules. Additionally, the linear shape and the small nonpolar methyl group allow slightly better dispersion interactions with n-octane than methanol’s –OH group. So acetonitrile is slightly more soluble than methanol.

  4. Cyclohexane (C6H12\text{C}_6\text{H}_{12}) — This is a cyclic alkane, completely nonpolar. Its molecules interact with each other only through dispersion forces — exactly the same type of interaction that holds n-octane molecules together. When mixed, cyclohexane and n-octane molecules can pack together almost as well as with themselves. There is no energy penalty for mixing; in fact, they are miscible in all proportions. This is the most soluble of the four.

Tip

A quick way to rank: count the number of polar groups vs. the size of the nonpolar hydrocarbon part. Cyclohexane has zero polar groups → most soluble. KCl is fully ionic → least soluble. Between methanol and acetonitrile, compare the strength of intermolecular forces in the pure solute: hydrogen bonds (stronger) vs. dipole-dipole (weaker). Weaker forces in the pure state mean easier dissolution in a nonpolar solvent. …

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