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Exercises · 1.10

Q.What role does the molecular interaction play in a solution of alcohol and water?

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Alcohol–water hydrogen bonds are weaker than the alcohol–alcohol and water–water bonds in the pure liquids, so molecules escape more easily, vapour pressure rises, and the mixture shows a positive deviation from Raoult's law.

Step 1 — Bonding in the pure liquids.

Both water and alcohol (ethanol) carry an O–H group, so molecules of each pure liquid are held together by strong hydrogen bonds, written as O–H⋯O. These bonds hold the molecules tightly and keep the escaping tendency (and hence the vapour pressure) of each pure liquid low.

Step 2 — What happens on mixing.

When alcohol and water are mixed, the original alcohol–alcohol and water–water contacts are partly replaced by new alcohol–water contacts. Alcohol and water molecules do form hydrogen bonds with each other, but these alcohol–water hydrogen bonds are weaker than the hydrogen bonds that existed in the two pure liquids.

Step 3 — Effect on escaping tendency.

Because the molecules in the mixture are, on average, held less tightly than in the pure liquids, they can leave the liquid surface more easily. The escaping tendency of both components rises above what it was in the pure state.

Step 4 — Effect on vapour pressure and Raoult's law. …

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