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Worked Examples · Example 5

Q.Find the amount and the compound interest on ₹8,000 for 1½ years at 10% per annum, compounded half-yearly.

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Given: P=8000P = 8000, nominal R=10%R = 10\% p.a., T=1.5T = 1.5 years, compounded half-yearly.

Adjust for half-yearly compounding. Rate per period r=102=5%r = \dfrac{10}{2} = 5\%; number of periods m=2×1.5=3m = 2 \times 1.5 = 3.

Method 1 — formula.

A=P(1+r100)m=8000(1.05)3=8000×1.157625=9261.A = P\left(1 + \dfrac{r}{100}\right)^{m} = 8000(1.05)^{3} = 8000 \times 1.157625 = 9261.

So CI=A−P=9261−8000=1261CI = A - P = 9261 - 8000 = 1261.

Method 2 — independent check (period-by-period).

  • After 1st half-year: 8000×1.05=84008000 \times 1.05 = 8400. …

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